Question

我们可以根据elif else调用方法吗...例如：

if line2[1] = '1': 
    a(line2) 
elif line2[1] = '2': 
    b(line2) 
elif line2[1] = '3': 
    c(line2)

然后列表继续。我们可以使用地图并调用该函数。说

线路输入示例：

line = [＆＃39; 1＆＃39;，＆＃39;说＆＃39;，＆＃39;嗨＆＃39;]

line = [＆＃39; 2＆＃39;，＆＃39; How＆＃39;，＆＃39; Are＆＃39;]

代码：

def g(line)
   my_map = { '1': a(line),
           '2': b(line),
           '3': c(line, b),
           ......
           and the list goes on
           }

   here if line[0] = '1' call a(line)
        elif line[0] = '2' call b(line)

如何根据输入调用函数。

如果可能，请发送示例代码

由于拉克什

line = [＆＃39; 1＆＃39;，＆＃39;说＆＃39;，＆＃39;嗨＆＃39;，＆＃39;＆＃39;，＆＃39;＆＃39; ，＆＃39;＆＃39;＆＃39;＆＃39;，＆＃39;＆＃39;，＆＃39;＆＃39;，....继续5-15次] 在上面的相同示例中，如果我还必须分配其他变量。我该怎么做。

if line2[1] == '8':
             p.plast = line2[3]
             p.pfirst = line2[4]
             p.pid = line2[9]

elif line2[1] == 'I':
             p.slast = line2[3]
             p.sfirst = line2[4]
             p.sid = line2[9]
 elif line2[1] == 'Q':
            p.tlast = line2[3]
             p.tfirst = line2[4]
             p.tid = line2[9]

是否也有解决方法。

Answer 1

更新：一种棘手的方法

def make_change(line, p):

    # Each value of the dict will be another dict in form property:index.
    # Where property is key of p object to be set/updated, index is index of line with which property should be updated.

    another_map = {
        "V": {'vlast': 3, 'vfirst': 5, 'vnone': 7},
        "S": {'slast':2, 'sfirst':9, 'snone':4}
    }

    val = another_map.get(line[1], None)
    if val is not None:
        # iterating over val items to get which property to set and index if line to set
        for key, item in val.iteritems():
            p[key] = line[item]

    print p


new_list = ["V", "S", 1,2,3,4,5,6,7,8,9,10,11,12,13]
make_change(new_list, {})

现在更改new_list[1]结束看输出

if line2[1] = '1': 
    a(line2) 
elif line2[1] = '2': 
    b(line2) 
elif line2[1] = '3': 
    c(line2)

将完美运作。

但是你的第二种方法不起作用，因为当你写my_map = { '1': a(line), ... }时，my_map['1']将是None或返回函数的值（因为你正在调用函数）

试试这个

def g(line):
    # Note that value of dict is only the name of the function.
    my_dict = {
      '1': a,
      '2': b
      ...
    }

   # Assuming line[0] is 1,2,3, etc. Check if corresponding function exists in map_dict 
   # Convert line[0] to string before passing it in dict.get() method
   call_func = my_dict.get(str(line[0]), None)
   if call_func is not None:
        call_func(line)

Answer 2

你有正确的想法，但是你有点错误 - 你应该传递一个函数对象，而不是调用它。

def g(line):
    my_map = {'1': a, '2': b, '3': c ... }
    cur_func = my_map.get(line)
    if cur_func is not None:
         cur_func(line)
    else:
         #No mapping found ..

if else python函数调用或方法调用

2 个答案: