Question

我有一个名为sso_med.txt的文件

        insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502683504',16,current_date, '502264160', current_date, '502264160');
        insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031',15,current_date, '502264160', current_date, '502264160');
        insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031',16,current_date, '502264160', current_date, '502264160');
        insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('212462117', 15, current_date, '502264160', current_date, '502264160');
        insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('212462117', 16, current_date, '502264160', current_date, '502264160');

我想在'502689031',16,current_date,

之间引入一个空格

所以我尝试了下面的命令

awk '{gsub(/,[0-9a-zA-Z]/, ", "); print}' sso_med.txt

但我没有得到我期待的东西

insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502683504', 6, urrent_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 5, urrent_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 6, urrent_date, '502264160', current_date, '502264160');

Answer 1

awk 解决方案：

awk '{ gsub(/, */, ", ", $0) }1' sso_med.txt

输出：

insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502683504', 16, current_date, '502264160', current_date, '502264160');
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 15, current_date, '502264160', current_date, '502264160');
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 16, current_date, '502264160', current_date, '502264160');

gsub(/, */, ", ", $0) - 使用单个尾随空格替换/ 重新排列 每个分隔符（即,）

Answer 2

请给出后面的参考：

awk '{gsub(/,[0-9a-zA-Z]/, " &"); print}' sso_med.txt

使用AWK和替换查找

2 个答案: