我有这个数据集:
> dput(SampleEvents)
structure(list(Event = structure(c(10L, 5L, 6L, 11L, 10L, 7L,
11L, 8L, 9L, 10L, 1L, 2L, 3L, 4L, 11L), .Label = c("e10", "e11",
"e12", "e13", "e2", "e3", "e6", "e8", "e9", "Login", "Logout"
), class = "factor"), Transaction.ID = structure(c(NA, 1L, NA,
2L, NA, NA, NA, NA, 3L, NA, NA, NA, NA, NA, NA), .Label = c("t1",
"t4", "t5"), class = "factor"), User.ID = structure(c(1L, 1L,
1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c("kenn1",
"kenn2"), class = "factor"), Event.Date = structure(c(1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "20/5/2017", class = "factor"),
Event.Time = structure(c(12L, 13L, 14L, 15L, 1L, 2L, 3L,
4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L), .Label = c("10:01", "10:02",
"10:03", "10:04", "10:05", "10:06", "10:07", "10:08", "10:09",
"10:10", "10:11", "9:00", "9:30", "9:45", "9:50"), class = "factor")), .Names = c("Event",
"Transaction.ID", "User.ID", "Event.Date", "Event.Time"), class = "data.frame", row.names = c(NA,
-15L))
我想删除"事件"列下两个固定值内的所有行,即"登录" to" Logout",它们之间的所有缺少的交易ID值都在"登录"和"退出":
我还想保留数据集的当前顺序。
我如何在R?
中执行此操作答案 0 :(得分:0)
您可以执行以下操作,该操作适用于您提供的数据......
library(dplyr)
#add variables to mark login-logout blocks and number them
df <- df %>% mutate(session=cumsum(Event=="Login")-cumsum(Event=="Logout"),
block=c(0,cumsum(diff(session)!=0)),
block=ifelse(Event=="Logout",block-1,block))
#identify blocks to remove
df2 <- df %>% group_by(block) %>%
summarise(Login=first(session)>0,
noTrans=all(is.na(Transaction.ID))) %>%
filter(Login & noTrans)
#remove unwanted blocks and delete temporary variables
df <- df %>% filter(!(block %in% df2$block)) %>%
select(-c(session,block))
df
Event Transaction.ID User.ID Event.Date Event.Time
1 Login <NA> kenn1 20/5/2017 9:00
2 e2 t1 kenn1 20/5/2017 9:30
3 e3 <NA> kenn1 20/5/2017 9:45
4 Logout t4 kenn1 20/5/2017 9:50
5 e8 <NA> kenn2 20/5/2017 10:04
6 e9 t5 kenn2 20/5/2017 10:05