Question

<?php    
    $abc = $objpdo->prepare("SELECT * FROM testdb.users WHERE user = ':login' AND user_pass=PASSWORD(':password')");
    $abc->bindParam(':login', $_POST['name']);
    $abc->bindParam(':password', $_POST['pw']);    
    $abc->execute(); 
    echo $abc->rowCount();
    // the example above doesn't work rowCount is always 0
    $abc = $objpdo->prepare("SELECT * FROM testdb.users WHERE user = '?' AND user_pass=PASSWORD('?')");
    $abc->execute([$_POST['name'], $_POST['pw']]);
    echo $abc->rowCount();
    // and again rowCount is always 0
    $abc = $objpdo->query("SELECT * FROM testdb.users WHERE user = '".$_POST['name']."' AND user_pass=PASSWORD('".$_POST['pw']."')");
    echo $abc->rowCount();
    // this thing here is working
?>

我在我的代码中准备好的陈述似乎不起作用，奇怪的是当我尝试运行query（）而没有准备它，只是直接将值传递给它工作的字符串。

请注意，我总是使用现有用户/密码尝试此代码。

Answer 1

占位符周围不需要引号，否则查询只会将它们视为字符串，而不是占位符。

$abc = $objpdo->prepare("SELECT * FROM testdb.users WHERE user = :login AND user_pass=PASSWORD(:password)");

与序数占位符（问号）相同：

$abc = $objpdo->prepare("SELECT * FROM testdb.users WHERE user = ? AND user_pass=PASSWORD(?)");

PHP PDO执行/准备似乎不起作用

1 个答案: