Question

我正在尝试将名称字段分隔到相应的字段中。名称字段不一致。它可以显示为 Doe III，John w 或 Doe，John，或 Doe III，John，或 Doe，John W 或者可能缺少后缀和/或中间首字母。任何想法将不胜感激。

SELECT (
        CASE LEN(REPLACE(FirstName, ' ', ''))
            WHEN LEN(FirstName + ' ') - 1
                THEN PARSENAME(REPLACE(FirstName, ' ', '.'), 2)
            ELSE PARSENAME(REPLACE(FirstName, ' ', '.'), 3)
            END
        ) AS LastName
    ,(
        CASE LEN(REPLACE(FirstName, ' ', ''))
            WHEN LEN(FirstName + ',') - 1
                THEN NULL
            ELSE PARSENAME(REPLACE(FirstName, ' ', '.'), 2)
            END
        ) AS Suffix
    ,PARSENAME(REPLACE(FirstName, ' ', '.'), 1) AS FirstName
FROM Trusts.dbo.tblMember

如上所述，无论格式如何，我都需要使用名称来解析LastName，Suffix，FirstName，MiddleInitial的相应字段，无论它是否具有后缀或中间的首字母

Answer 1

如果给定的4个名称是唯一的案例类型，那么您可以使用类似下面的内容。

注意：我使用CTE表tbl2来区分comma_pos，first_space，second_space，以便更好地理解主查询。您可以将主查询中的这些值替换为CTE中的相应函数，以使主查询更快。我的意思是在主查询中用comma_pos替换charindex(',',name)，依此类推。

此外，我假设name列中没有前导/尾随或额外的空格或任何垃圾字符。如果有，请在继续之前先清理数据。

Rexter Sample

with tbl2 as (
select tbl.*,
    charindex(',',name) as comma_pos,
    charindex(' ',name,1) first_space,
    charindex(' ',name,charindex(' ',name,1)+1) second_space
from tbl)

select tbl2.name

,case when second_space <> 0
        then substring(name,comma_pos+1,second_space-comma_pos-1)
      when first_space > comma_pos
        then substring(name,comma_pos+1,first_space-comma_pos-1)
      else substring(name,comma_pos+1,len(name)-comma_pos)
end as first_name

,case when second_space <> 0
        then substring(name,second_space+1,len(name)-second_space)
      when first_space > comma_pos
        then substring(name,first_space+1,len(name)-first_space)
      end as middle_name
,case when first_space=0 or first_space>comma_pos
    then substring(name,1,comma_pos-1)
    else substring(name,1,first_space-1) 
end as last_name
,case when first_space=0 or first_space>comma_pos
    then null
    else substring(name,first_space,comma_pos-first_space) 
end as suffix

from  tbl2;

在SQL

1 个答案: