Question

我正在尝试制作游戏，在开始时，第一部分很好，但是，我无法使第二个问题正常工作，我希望它能显示：rules_yes如果输入是（不区分大小写），则rules_no如果还有其他内容，则显示目前，无论我为规则输入什么，它只运行rules_yes。我可以获得一些关于如何使其工作的反馈吗？

numpy array

Answer 1

因为您将（Y / N）问题值添加到“yes_no”参数，但是您的'if-else'条件使用'input'，因此输入未初始化，这意味着它等于0.这就是为什么您的问题总是返回YES。

更改您的代码：

public static void main(String[] args) {

    String user_name;
    String name_answer;
    String yes_no;
    String rules_yes;
    String rules_no;
    char[] input;
    char Yes = 0;

    {
        user_name = JOptionPane.showInputDialog("Enter Your Name");

        name_answer = ("Hello " + user_name + " Welcome to Tic-Tac-Toe, Click OK to Start");

        JOptionPane.showMessageDialog(null, name_answer);
    }

    {
        yes_no = JOptionPane.showInputDialog("Would you like the rules (Y/N)");

        input = yes_no.toCharArray();
        if (input[0] == Yes) {

            rules_yes = ("Yes? The Rules: X goes first, each player takes turns to put their symbol in one of nine boxes, you cannot put your symbol in a box which already contains a symbol, the first one to make a row of three wins");

            JOptionPane.showMessageDialog(null, rules_yes);
        } else {

            rules_no = ("No? Well too bad, here are the rules, The Rules: X goes first, each player takes turns to put their symbol in one of nine boxes, you cannot put your symbol in a box which already contains a symbol, the first one to make a row of three wins");

            JOptionPane.showMessageDialog(null, rules_no);
        }
    }
}

Answer 2

为什么使用＆＃34;输入＆＃34;对话框？

更简单的解决方案是使用＆＃34;消息＆＃34;对话框＆＃34;是＆＃34;，＆＃34;否＆＃34;用户点击的按钮。

阅读How to Make Dialogs上Swing教程中的部分，了解更多信息和示例。

Answer 3

您的代码存在许多问题，您可以采取许多措施来简化代码。

yes和Yes未初始化，导致您的程序失败。
您可以将yes_no声明为String，然后使用if (yes_no.equalsIgnoreCase("y");（而不是使用char yes和char Yes）
这不会影响你的程序，但你的行之间有很多间距，这使它看起来比它更多。
input是不必要的，因此您可以将其删除。

所以你的最终代码可能如下所示：

import javax.swing.JOptionPane;

public class ScratchPaper {
    public static void main(String[]args) {
        String userName;
        String nameAnswer;
        String rulesYes;
        String rulesNo;
        String yesNo;

        userName = JOptionPane.showInputDialog("Enter Your Name");
        nameAnswer = ("Hello " + userName + " Welcome to Tic-Tac-Toe, Click OK to Start");
        JOptionPane.showMessageDialog( null, nameAnswer );
        yesNo = JOptionPane.showInputDialog("Would you like the rules (Y/N)");


        if (yesNo.equalsIgnoreCase("y")) 
        {
            rulesYes = ("Yes? The Rules: X goes first, each player takes turns to put their symbol in one of nine boxes, you cannot put your symbol in a box which already contains a symbol, the first one to make a row of three wins");
            JOptionPane.showMessageDialog( null, rulesYes );
        }
        else {
            rulesNo = ("No? Well too bad, here are the rules, The Rules: X goes first, each player takes turns to put their symbol in one of nine boxes, you cannot put your symbol in a box which already contains a symbol, the first one to make a row of three wins");
            JOptionPane.showMessageDialog( null, rulesNo );
        }
    }
}

如果您有任何疑问，请在下面发表评论，我会尽快回答。谢谢！

游戏的JOption Panel

3 个答案: