Question

我使用的是Javascript InfoVis SpaceTree。我有一棵树，如下所示：

http://zygonia.net/so/ex2.html

但是，我想选择“NOW”节点，以便突出显示返回根节点的路径，但阻止此节点居中。即：

http://zygonia.net/so/ex3.html

我尝试了setPos()，但这不起作用。

有什么想法吗？

添加屏幕上限，以防链接消失：

enter image description here

Answer 1

啊，那又搞乱了图库：D

让我们再看看那个select函数，特别是onComplete回调函数：

onComplete: function(){ // what a mess!
    group.hide(group.prepare(getNodesToHide.call(that)), complete); // hide the nodes???
    geom.setRightLevelToShow(node, canvas); // guess what this already moves stuff around!
    that.compute("current"); // recomputes the graphs position
    that.graph.eachNode(function(n) { // sets up the moved node positions
        var pos = n.pos.getc(true);
        n.startPos.setc(pos.x, pos.y);
        n.endPos.setc(pos.x, pos.y);
        n.visited = false; 
    });

    // hey look! We don't use a global translation offset! So we need to translate the HTML stuff extra
    var offset = { x: complete.offsetX, y: complete.offsetY };
    that.geom.translate(node.endPos.add(offset).$scale(-1), ["start", "current", "end"]);

    // show the nodes again?
    group.show(getNodesToShow.call(that));              

    // the first useful call in here, redraw the updated graph!
    that.plot();
    complete.onAfterCompute(that.clickedNode); // callback better leave them here
    complete.onComplete();
}

因此，既然您根本不需要任何重新定位，我们可以重构（也称为删除某些行）：

onComplete: function(){             
    that.plot();
    complete.onAfterCompute(that.clickedNode);
    complete.onComplete();
}

看吧！我节省了大量的字节！这就是所有需要休息的事情并没有对图表做任何重要的事情。

当然，摆脱这些功能可能会让某些人感到厌烦，所以我们应该向center添加select个参数：

select: function(id, center, onComplete) {

....

onComplete: function(){
    if (center) {
        group.hide(group.prepare(getNodesToHide.call(that)), complete);
        geom.setRightLevelToShow(node, canvas);
        that.compute("current");
        that.graph.eachNode(function(n) { 
            var pos = n.pos.getc(true);
            n.startPos.setc(pos.x, pos.y);
            n.endPos.setc(pos.x, pos.y);
            n.visited = false; 
        });
        var offset = { x: complete.offsetX, y: complete.offsetY };
        that.geom.translate(node.endPos.add(offset).$scale(-1), ["start", "current", "end"]);
    }
    group.show(getNodesToShow.call(that));              
    that.plot();
    complete.onAfterCompute(that.clickedNode);
    complete.onComplete();
}

Answer 2

设置offSetX和offSetY位置，如下所示：

var st = new $jit.ST({
    'injectInto': 'infovis',
    //set duration for the animation
    duration: 800,
    //set animation transition type
    transition: $jit.Trans.Quart.easeInOut,
    //set distance between node and its children
    levelDistance: 50,
    //set max levels to show. Useful when used with
    //the request method for requesting trees of specific depth
    levelsToShow: 4,
    orientation: 'top',
    align: 'center',
    //set node and edge styles
    //set overridable=true for styling individual
    //nodes or edges 
    offsetX: 0, offsetY: 110,
    Node: {
        height: 30,
        width: 31,
        //use a custom
        //node rendering function
        type: 'nodeline',
        color: '#f76b14',
        lineWidth: 1,
        align: "center",
        overridable: true
    },

infovis div，即持有spacetree的div不会有时显示整个图形。在onComplete事件中添加以下代码就可以了。

这将设置div的高度以适应整个图形。我使用的方向是“顶部”。

onComplete: function () {
        var LastnodeTop = 0;
        $("div.node").each(function () {
            var pos = $(this).position();
            if (pos.top > LastnodeTop)
                LastnodeTop = pos.top;
        });
        var LastnodeTopStr = LastnodeTop.toString();
        LastnodeTopStr = LastnodeTopStr.substring(0, 4);
        var LastnodeTopInt = parseInt(LastnodeTopStr) + 100;            
        $("#infovis").attr("style", "height:" + LastnodeTopInt + "px");
    }

感谢。

Javascript InfoVis SpaceTree：阻止选定的节点以画布为中心

2 个答案: