Question

我有一个问题，我在创建新对象并尝试使用Spring data-jpa使用分离对象保存它。

我的方案是属于特定状态的用户，并且该用户可以更改配置。如果用户尝试更改配置并且配置不存在，则需要使用该状态创建新配置。

但是当我尝试这样做时，我会收到以下错误：

org.hibernate.PersistentObjectException: detached entity passed to persist: com.testproj.tester.pojo.EvState
    org.hibernate.event.internal.DefaultPersistEventListener.onPersist(DefaultPersistEventListener.java:124)
    org.hibernate.internal.SessionImpl.firePersist(SessionImpl.java:765)
    org.hibernate.internal.SessionImpl.persist(SessionImpl.java:758)
    org.hibernate.jpa.event.internal.core.JpaPersistEventListener$1.cascade(JpaPersistEventListener.java:80)
    org.hibernate.engine.internal.Cascade.cascadeToOne(Cascade.java:398)
    org.hibernate.engine.internal.Cascade.cascadeAssociation(Cascade.java:323)
    org.hibernate.engine.internal.Cascade.cascadeProperty(Cascade.java:162)
    org.hibernate.engine.internal.Cascade.cascade(Cascade.java:111)

努力

我在这里创建了所有jparepositories是配置和状态的代码：

@Entity
@Table(name = "ev_layout_configuration")
public class EvConfiguration {
    .....

    @OneToOne(cascade = { CascadeType.MERGE, CascadeType.PERSIST })
    private EvState evState;

    ...

}

我也尝试过cascadeType.ALL。

@Entity
@Table(name = "ev_state")
public class EvState {

    @Id
    @GeneratedValue(generator = "sequence")
    @GenericGenerator(name = "sequence", strategy = "sequence", parameters = {
            @Parameter(name = "sequence", value = "ev_vahan_sequence") })
    @Column(name = "id")
    private Long id;

    @Column(name = "state_tin_code")
    private Integer stateTinCode;

    @Column(name = "state_name")
    private String stateName;

    @Column(name = "state_short_name")
    private String stateShortName;

    @Column(name = "updated_by")
    private String updatedBy;

    .....
}

saveConfiguration code

User user = (User) SecurityContextHolder.getContext().getAuthentication().getPrincipal();

EvUser evUser = userRepository.findByEmail(user.getUsername());
evConfiguration = evConfigurationRepository.findByEvState(evUser.getEvState());
System.out.println("============================User from State : " + evUser.getEvState().getStateName()
                    + " =============================");
if (evConfiguration == null) {
    evConfiguration = new EvConfiguration();
    evConfiguration.setState(evUser.getEvState());
    evConfiguration = evConfigurationRepository.save(evConfiguration);
}

请朋友帮助我。我正在使用spring data-jpa和hibernate和postgres。

Spring Boot，Spring data-jpa分离实体传递给persist

0 个答案: