Question

以下是用于搜索列的查询结果

background-color:red;

这非常适合查找/搜索，所使用的查询位于

之下

DECLARE @Temp TABLE (
    [CoreTable] VARCHAR(250),
    [CoreTableDecription] VARCHAR(250),
    [FieldName] VARCHAR(250),
    [cnt] VARCHAR(250)
                 )
declare @Keyword1 VARCHAR(100) = '%Prob%'
declare @Keyword2 VARCHAR(100) = '%Prob%'
--------------------------------------------------------------
INSERT INTO @Temp (CoreTable, CoreTableDecription, FieldName, cnt)
 VALUES 

('PRO','PROTOS_PersonalInformation','AnyCommunicationProblem','1'),
('PRO','PROTOS_PersonalInformation','SightProblems','1'),
('PRO','PROTOS_PersonalInformation','SpeechProblems','1'),
('PRO','PROTOSMODEL_Antenatal_Status','Other_Antenatal_Problems','1'),
('PRO','PROTOSMODEL_Antenatal_Status','Other_Antenatal_Problems_Text','1'),
('PRO','PROTOSMODEL_Baby_Details','Neonatal_medical_problems','1'),
('PRO','PROTOSMODEL_Baby_Details','Neonatal_medical_problems_Text','1'),
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected','1'),
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Bruising','1'),
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Naevus','1'),
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Rash','1'),
('PRO','PROTOSMODEL_Baby_Postnatal','Any_skin_problems_detected_Text','1')

Select * from @Temp

然而，我需要做的是运行手动查询来确定列/表中的值（见下文）：

declare @Keyword1 VARCHAR(100) = '%Prob%'
declare @Keyword2 VARCHAR(100) = '%Prob%'
select 
    LEFT(o.name,3) CoreTable,
    o.name CoreTableDesc,
    --o.name AS TableName,
    c.name AS FieldName 
    ,COUNT(c.name) cnt
    from sys.columns c
        inner join sys.objects  o on c.object_id=o.object_id
    where c.name LIKE @Keyword1 
    and LEFT(o.name,3)     in ('PRO')
    and c.name LIKE @Keyword2
    GROUP BY c.name, LEFT(o.name,3), o.name
--  order by LEFT(o.name,3), c.name

这只返回行NULL - 2682，No - 87687，Yes - 135478

我想知道是否有办法从显示表名和列名的第一个查询的结果中自动执行此操作

Answer 1

谢谢以下所有答案，但我不确定如何计算

中的数据项

DECLARE 
@TABLENAME VARCHAR(255),
@FIELDNAME VARCHAR(255),
@SQL VARCHAR(MAX),
@FieldNamePart1 as varchar(50),
@FieldNamePart2 as varchar(50) 

SET @SQL = ''
SET @FieldNamePart1 = 'Type'
SET @FieldNamePart2 = 'Method'

IF @FieldNamepart2 = ''
       DECLARE CRS CURSOR FOR
       SELECT TABLE_NAME, COLUMN_NAME
       FROM INFORMATION_SCHEMA.COLUMNS
       WHERE CHARINDEX('PROTOSMODEL',TABLE_NAME) <> 0
              AND CHARINDEX(@FieldNamePart1, COLUMN_NAME) <> 0
 --             AND CHARINDEX('DATE', COLUMN_NAME) = 0
 --             AND CHARINDEX('TIME', COLUMN_NAME) = 0
ELSE
       DECLARE CRS CURSOR FOR
       SELECT TABLE_NAME, COLUMN_NAME
       FROM INFORMATION_SCHEMA.COLUMNS
       WHERE CHARINDEX('PROTOSMODEL',TABLE_NAME) <> 0
              AND CHARINDEX(@FieldNamePart1, COLUMN_NAME) <> 0
              AND CHARINDEX(@FieldNamePart2, COLUMN_NAME) <> 0
 --             AND CHARINDEX('DATE', COLUMN_NAME) = 0
 --             AND CHARINDEX('TIME', COLUMN_NAME) = 0

OPEN CRS

FETCH NEXT FROM CRS INTO @TABLENAME, @FIELDNAME

WHILE @@FETCH_STATUS = 0
BEGIN
--     SET @SQL = @SQL + CAST('SELECT DISTINCT ''' AS VARCHAR(MAX)) + CAST(@TABLENAME AS VARCHAR(MAX)) + CAST(''' AS PROTOSMODEL_TABLE, ''' AS VARCHAR(MAX)) + CAST(@FIELDNAME AS VARCHAR(MAX)) + CAST(''' AS PROTOSMODEL_FIELD, ' AS VARCHAR(MAX)) + CAST(@FIELDNAME AS VARCHAR(MAX)) + CAST(' AS FIELD_VALUE FROM ' AS VARCHAR(MAX)) + CAST(@TABLENAME AS VARCHAR(MAX)) + CAST(' UNION ALL ' AS VARCHAR(MAX))
       SET @SQL = @SQL + 'SELECT DISTINCT ''' + @TABLENAME + ''' AS PROTOSMODEL_TABLE, ''' + @FIELDNAME + ''' AS PROTOSMODEL_FIELD, [' + @FIELDNAME + '] AS FIELD_VALUE FROM ' + @TABLENAME + ' UNION ALL ' 
       FETCH NEXT FROM CRS INTO @TABLENAME, @FIELDNAME
END
CLOSE CRS
DEALLOCATE CRS
SET @SQL = SUBSTRING(@SQL, 1, LEN(@SQL) - 10)
EXEC (@SQL)
GO

是否可以从查询中返回的表和字段返回结果

1 个答案: