Question

这是我刚刚制作的控制器，用于检查输入密码。它似乎没有错误。但是，当我运行它时，它没有收到结果（echo＆＃34;正确的密码＆＃34;）虽然我输入了正确的输入。

namespace App\Http\Controllers;

use Illuminate\Http\Request;

class MainController extends Controller
{
private $data = array(
    array("TestUser","Password"),
    array("Admin","BigA1r")
);
//$this->log($u,$p);    
public static function log($username,$pass) { //login
    echo "<title>Processing request...</title>";
    echo "Logging in... Please wait.";
    for ($i = 1;$i == 35;$i++){
            $u = $data[$i][1];
            if ($u == $username){
                $p = $data[$i][2];
                if ($p == $pass){
                    setcookie("username="+$u);//+";password="+p;
                    echo "Right password";
                }else{echo "Wrong password";};
            }else{
                echo "Can't find this username. Please try a different 
name.";
            }       
    }   
}

这里的错误是什么？我无法找到它。并没有抛出任何东西。它只是停留在回声＆＃34;登录...请等待。＆＃34 ;;

Answer 1

您的代码中有几个问题，例如

使用self::$data代替$data。阅读How to access private variable in static function
循环条件为count(self::$data)
密码的未定义索引问题，因为索引从0开始

所以，试试下面的代码

for ($i = 0,$l=count(self::$data);$i < $l;$i++){
   $u = self::$data[$i][0]; // use 0 not 1 for username, as index start from 0
   if ($u == $username){
       $p = self::$data[$i][1]; // use 1 not 2, as index start from 0
       if ($p == $pass){
          setcookie("username="+$u);//+";password="+p;
          echo "Right password";
       } else{echo "Wrong password";};
   } else{
       echo "Can't find this username. Please try a different name.";
   }       
} //end for

并将您的私有变量$data设为static，

private static $data = array(
    array("TestUser","Password"),
    array("Admin","BigA1r")
);

完整代码，

class MainController extends Controller {
    private static $data = array(
        array("TestUser","Password"),
        array("Admin","BigA1r")
    );
    //$this->log($u,$p);    
    public static function log($username,$pass) { //login
        echo "<title>Processing request...</title>";
        echo "Logging in... Please wait.";
        for ($i = 0,$l=count(self::$data);$i < $l;$i++){
            $u = self::$data[$i][0];
            if ($u == $username){
                $p = self::$data[$i][1];
                if ($p == $pass){
                    setcookie("username="+$u);//+";password="+p;
                    echo "Right password";
                } else {
                    echo "Wrong password";
                }
            } else {
                echo "Can't find this username. Please try a different name.";
            }
        } // end for loop  
    } // end function log
} // end class MainController

Answer 2

尝试使用：

self::$data[$i][1] and self::$data[$i][2]

要从静态方法访问类的私有变量，您需要使用self关键字。

此外，在循环中你有

for ($i = 1;$i == 35;$i++)

这可能会失败，因为条件是$ i == 35而你的开头是$ i = 1，这是永远不会满足的，应该是$ i＆lt; = 35。

PHP：控制器不工作

2 个答案: