Question

我有一个＆＃34; transaction_status＆＃34;表：

id  transaction_id  status
1         12           0
2         13           0
3         12          -1
4         14           0
5         13          -1
6         15           0
[END OF TABLE]

我需要获取只有status = 0的记录的事务ID。

例如，我正在寻找上表：

id   transaction_id   status
4          14            0
6          15            0

到目前为止，我正在尝试：

SELECT id, transaction_id, status  
FROM transaction_status
WHERE status = 0 OR status = -1
ORDER BY status ASC
GROUP BY txn_id
HAVING status = 0

但没有运气。我的想法已经不多了。有什么想法吗？谢谢！

Answer 1

对having子句做了一些小改动。

SELECT id, transaction_id, status  
FROM transaction_status
WHERE status = 0 OR status = -1
GROUP BY transaction_id
HAVING min(status) = 0

编辑：也删除顺序，因为它没有任何意义

Answer 2

使用GROUP BY并在having子句中检查min和max状态为0。

<强>查询

select  `transaction_id`
from `your_table_name`
group by`transaction_id`
having min(`status`) = 0 and max(`status`) = 0;

Answer 3

我认为处理此问题的最简单方法是使用transaction_id的条件聚合，并计算哪些ID只与其关联的状态为0。在子查询中执行此操作，然后联接回主表以检索所需的完整匹配记录。

SELECT t1.*
FROM transaction_status t1
INNER JOIN
(
    SELECT transaction_id
    FROM transaction_status
    GROUP BY transaction_id
    HAVING SUM(CASE WHEN status <> 0 THEN 1 ELSE 0 END) = 0
) t2
    ON t1.transaction_id = t2.transaction_id
ORDER BY t1.id DESC

获取记录GROUPing BY并丢弃重复项

3 个答案: