您好我是PHP的新手,想知道如何在同一个数组中找到特定的token
和token_time
。例如,如何在下面的数组中找到token
值440745553780011a38b207466e2dae1a
以及token_time
值1495672355
并显示它们?
阵列
array (size=1)
'token' =>
array (size=4)
0 =>
array (size=2)
'token' => string '04a1dd0991b366fdc4d7d46fcff03cb3' (length=32)
'token_time' => int 1495672339
1 =>
array (size=2)
'token' => string '80d84dc863cbbeaef0c9a448f7865352' (length=32)
'token_time' => int 1495672345
2 =>
array (size=2)
'token' => string '440745553780011a38b207466e2dae1a' (length=32)
'token_time' => int 1495672355
3 =>
array (size=2)
'token' => string '766ac765d2a34e01cd954444d5895208' (length=32)
'token_time' => int 1495672525
答案 0 :(得分:2)
令人惊讶的是,您可以像往常一样使用array_search()但使用数组:
$id = array_search([
'token' => '440745553780011a38b207466e2dae1a',
'token_time' => 1495672355
], $array['token']);
$id
将包含两个值都存在的数组的id。然后,您可以像这样访问它:
$array['token'][$id];
这些术语甚至不需要在正确的顺序中或在针阵列中输入:
$id = array_search([
'token_time' => '1495672355', //passed as string, whereas array has these as ints
'token' => '440745553780011a38b207466e2dae1a'
], $array['token']);
答案 1 :(得分:1)
这是一个完成你需要的功能:
function findToken(&$array, $token, $time){
foreach($array['token'] as $data){
if($data['token'] == $token && $data['token_time'] == $time){
return $data;
}
}
return null;
}
以下是如何使用它:
$token = findToken($array, '440745553780011a38b207466e2dae1a', '1495672355');
if($token){
echo "Found token";
} else {
echo "Token not found";
}