Question

我尝试在我的电脑上连接php，但Android代码将停在public String doInBackground(Void... arg0){ HttpURLConnection con = null; String urlString = "http://localhost:8081/PHP/Android_SQL.php"; System.out.println("before try"); String res = ""; try { URL url = new URL(urlString); con = (HttpURLConnection) url.openConnection(); con.setReadTimeout(15000); con.setConnectTimeout(10000); con.setRequestMethod("GET"); //set input and output descript con.setDoInput(true); con.setDoOutput(false); // in needed? System.out.println("connecting"); con.connect(); // won't work System.out.println("connect "); System.out.println(con.getURL()); BufferedReader br = new BufferedReader(new InputStreamReader(con.getInputStream(), "UTF-8")); StringBuilder sb = new StringBuilder(); String line = null; while ((line = br.readLine()) != null) { System.out.println(line); sb.append(line + "\n"); System.out.println(line); } json = sb.toString(); br.close(); return json; }catch (SocketTimeoutException a){ a.getMessage(); }catch (IOException b){ b.getMessage(); }catch (Exception e) { e.getMessage(); } finally { System.out.println("sueecssful"); } return null; } 我不知道它发生了什么。

05-24 20:27:44.032 3089-3089/com.example.user.tophp I/System.out: click the button
05-24 20:27:44.033 3089-3237/com.example.user.tophp I/System.out: before try
05-24 20:27:44.033 1524-1595/system_process W/AudioTrack: AUDIO_OUTPUT_FLAG_FAST denied by client
05-24 20:27:44.033 3089-3237/com.example.user.tophp I/System.out: connecting
05-24 20:27:44.036 3089-3237/com.example.user.tophp I/System.out: sueecssful

我发现其中一个问题是SSL认证？

logcat：

Vagrant.configure("2") do |config|
  config.vm.network "forwarded_port", guest: 2003, host: 12003, protocol: "tcp"
  config.vm.network "forwarded_port", guest: 2003, host: 12003, protocol: "udp"
end

Answer 1

您正在尝试连接到localhost:8081，而adb本身就是Android设备。

使用localhost通过USB向您的计算机移出正向/反向，或者只需将192.168.0.2:8081替换为本地网络上计算机的IP 即可。示例：catch (SocketTimeoutException a){ a.getMessage(); }catch (IOException b){ b.getMessage(); }catch (Exception e) { e.getMessage(); }

其他潜在问题：

a.getMessage();

至少将a.printStackTrace()替换为Log.e("MyTag", "Error", a);以打印错误。但实际上你应该使用catch (SocketTimeoutException a){ Log.e("MyTag", "Timout Error", a); }catch (IOException b){ Log.e("MyTag", "IO Error", b); }catch (Exception e) { Log.e("MyTag", "Error", e); } * https://developer.android.com/reference/android/util/Log.html

<uses-permission android:name="android.permission.INTERNET"/>

另外，请确保在清单{{1}}

中添加了以下内容

HttpURLConnection connect（）不起作用

1 个答案: