Question

我有一个创建xml文档的小脚本，并使用doc = lxml.etree.SubElement(root, 'dependencies') for depen in dependency_list: dependency = lxml.etree.SubElement(doc, 'dependency') lxml.etree.SubElement(dependency, 'groupId').text = depen.group_id lxml.etree.SubElement(dependency, 'artifactId').text = depen.artifact_id lxml.etree.SubElement(dependency, 'version').text = depen.version if depen.scope == 'provided' or depen.scope == 'test': lxml.etree.SubElement(dependency, 'scope').text = depen.scope exclusions = lxml.etree.SubElement(dependency, 'exclusions') exclusion = lxml.etree.SubElement(exclusions, 'exclusion') lxml.etree.SubElement(exclusion, 'groupId').text = '*' lxml.etree.SubElement(exclusion, 'artifactId').text = '*' tree.write('explicit-pom.xml' , pretty_print=True)生成格式正确的xml文档。但是，选项卡缩进是2个空格，我想知道是否有办法将其更改为4个空格（我认为它看起来更好4个空格）。有没有一种简单的方法来实现它？

代码段：

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Answer 1

如果有人仍在尝试实现此目标，则可以使用lxml 4.5中的cond = df1['A'] >= df1['A'].shift(-1) + 4方法来完成-

etree.indent()

https://lxml.de/tutorial.html#serialisation

Answer 2

python lxml API似乎无法做到这一点。

标签间距的可能解决方案是：

def prettyPrint(someRootNode):
    lines = lxml.etree.tostring(someRootNode, encoding="utf-8", pretty_print=True).decode("utf-8").split("\n")
    for i in range(len(lines)):
        line = lines[i]
        outLine = ""
        for j in range(0, len(line), 2):
            if line[j:j + 2] == "  ":
                outLine += "\t"
            else:
                outLine += line[j:]
                break
        lines[i] = outLine
    return "\n".join(lines)

请注意，这不是很有效。只有在lxml C代码中本机实现此功能时，才能实现高效率。

在python lxml prettyprint中更改选项卡间距

2 个答案: