Question

所以我对我的API有这个ajax GET请求：

$(document).ready(function() {

//id=$("#id").val();
url="api.php/fcomment/"+5;
$.ajax({
type: "GET",
url: url,
dataType: "json",
contentType: "application/json; charset=utf-8",
success: function (data) 
    {
        console.log(data);
        alert(data);
        $('.greeting-content').append(data.comment);  
    }
});
});

我收到JSON数据，结果是：

[{"id":"5","comment":"Test","post_date":"18:17 18.05.2017","forum":"2","user":"0"},{"id":"8","comment":"Test2","post_date":"18:05 24.05.2017","forum":"2","user":"7"}]

我想从JSON格式中获取值，但没有任何内容添加到div。如果我在数据周围添加JSON.stringify，那么我得到整个JSON，但我需要每个属性

Answer 1

您访问data.comment这是未定义的访问权限，如data[0].comment

 $('.greeting-content').append(data[0].comment);

您可以使用$.each获取所有数据

data = [{"id":"5","comment":"Test","post_date":"18:17 18.05.2017","forum":"2","user":"0"},{"id":"8","comment":"Test2","post_date":"18:05 24.05.2017","forum":"2","user":"7"}];

console.log(data[0].comment);

$.each(data,function(i,v){
  
       console.log(data[i].comment);
 });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 2

你正在收集你需要的回合

    $.each(JSON.parse(data), function (i, data) {

                var row = data;   // data.comment
                console.log(row);
            });

OR

 $.each(data, function (i, data) {

                var row = data;
                console.log(row);
            });

无法从Ajax响应中获取数据

2 个答案: