Question

我想在我的应用程序中实现身份验证，我不知道用户输入的检查名称和密码是如何与数据库中的相同，而且我不知道如何在php文件中查询一定是。在表'client'的数据库中，我有NomClient和mdp（密码）。

的login.html

<ion-content class="padding" ng-controller="loginCtrl">
<div class="list list-inset" >
<label class="item item-input">
      <input type="text" placeholder="nom" required="" ng-model="NomClient"> 
</label> 
<label class="item item-input">
      <input type="password" placeholder="Password" ng-model="mdp"> 
</label> 
    <button class="button button-block button-positive" ng-click="submit()">Login</button>       
 </ion-content>

app.js

app.controller('loginCtrl', function($scope,$state,$http){
  $scope.submit= function(){
    $http.post(  
                "http://localhost/deb/login.php",  
                {
                'NomClient':$scope.NomClient,
                'mdp':$scope.mdp
                }  
           ).success(function(data){  
           }

  };

的login.php

 <?php    
 $connect = mysqli_connect("localhost", "root", "", "tem");  

$data = json_decode(file_get_contents("php://input"));
if(count($data) > 0)  
 {  
$NomClient = mysqli_real_escape_string($con, $data->N);NomClient
$mdp = mysqli_real_escape_string($con,$data->mdp);


$query =("??");
$que = mysqli_query($con, $query);
$count = mysqli_num_rows($que);

if($count==1){
echo 'correct';}
else{
echo 'wrong';
}

}
 ?>

Answer 1

你需要在php这样的查询你插入密码转换md5就像查询没有查询你可以删除md5函数。

     $convertmd5 = md5($mdp);
     $query ="SELECT * FROM `youtblname` where NomClient ='$NomClient' and mdp='$convertmd5'";

Answer 2

$response['status'] = 0;
$response['message'] = '';

$NomClient = $_POST['NomClient'];
$mdp = md5($_POST['mdp']);

$query = 'SELECT * FROM `client` WHERE NomClient = "'.$NomClient.'" AND   mdp= "'.$mdp.'"';

$connect = mysqli_connect("localhost", "root", "", "tem");
if(mysqli_connect_errno()){
    $response['status'] = 0;
    $response['message'] = "Failed to connect to MySQL: ".mysqli_connect_error();
    echo jsone_encode($response);exit;
}

$result = mysqli_query($connect, $query);
$rowcount=mysqli_num_rows($result);
if($rowcount>0){
    $response['status'] = 1;
    $response['message'] = 'Login successful';
}
else{
    $response['status'] = 0;
    $response['message'] = 'Invalid username of password';
}

echo json_encode($response);exit;

使用AngularJs和PHP进行身份验证

2 个答案: