Question

我尝试使用ifft和Julia计算系数数组的逆傅里叶变换。

我在数组上有N个复数，组织为：Y=[Y_0,.., Y_(N-1)]表示我的傅里叶系数并通过计算

ifft(Y)

我收到以下错误消息：

MethodError: no method matching plan_bfft(::Array{Complex,1},
::UnitRange{Int64}) Closest candidates are:  
plan_bfft{T<:Union{Complex{Float32},Complex{Float64}},N}(::Union{Base.ReshapedArray{T<:Union{Complex{Float32},Complex{Float64}},N,A<:DenseArray,MI<:Tuple{Vararg{Base.MultiplicativeInverses.SignedMultiplicativeInverse{Int64},N}}},DenseArray{T<:Union{Complex{Float32},Complex{Float64}},N},SubArray{T<:Union{Complex{Float32},Complex{Float64}},N,A<:Union{Base.ReshapedArray{T,N,A<:DenseArray,MI<:Tuple{Vararg{Base.MultiplicativeInverses.SignedMultiplicativeInverse{Int64},N}}},DenseArray},I<:Tuple{Vararg{Union{Base.AbstractCartesianIndex,Colon,Int64,Range{Int64}},N}},L}},
::Any; flags, timelimit) at fft/FFTW.jl:601  
plan_bfft{T<:Real}(::AbstractArray{T<:Real,N}, ::Any; kws...) at
dft.jl:205  
plan_bfft{T<:Union{Integer,Rational{T<:Integer}}}(::AbstractArray{Complex{T<:Union{Integer,Rational}},N},
::Any; kws...) at dft.jl:207   ...

in #plan_ifft#15(::Array{Any,1}, ::Function, ::Array{Complex,1},
::UnitRange{Int64}) at ./dft.jl:268  in #plan_ifft#3(::Array{Any,1},
::Function, ::Array{Complex,1}) at ./dft.jl:58  in
ifft(::Array{Complex,1}) at ./dft.jl:56

有人可以帮忙吗？

当我问typeof(Y)答案是Array {Complex，1}时。

谢谢

Answer 1

这里只是猜测：ifft期望数组元素的类型为Complex{Float64}，而不是Complex。此外，

julia> Complex<:Complex{Float64}
false

你是如何获得Complex数组的？

使用Complex{Float64}时，一切正常：

julia> Y=complex([1.,2.,3.],[4.,3.,2.])
3-element Array{Complex{Float64},1}:
 1.0+4.0im
 2.0+3.0im
 3.0+2.0im

julia> ifft(Y)
3-element Array{Complex{Float64},1}:
       2.0+3.0im     
 -0.788675+0.211325im
 -0.211325+0.788675im

与Julia一起使用ifft时出错

1 个答案: