在我的项目中,我使用谷歌几何定位API在地图上使用站点名称而不是纬度和经度显示标记。它工作正常。现在,我想在我的数据库字段resp上显示不同站点的不同标记。如果resp大于50,则标记为红色,如果小于50,则标记为绿色。我尝试了如下代码。但它显示所有绿色或全红色。如果resp的第一个值低于50,那么所有标记都是绿色,如果第一个值大于50,则所有标记都是红色。如何动态显示标记作为resp的值?请帮我。我的代码是
<script>
$(document).ready(function () {
var map;
var elevator;
var myOptions = {
zoom: 4,
center: new google.maps.LatLng(39.639537564366684, -97.03125),
mapTypeId: 'terrain'
};
map = new google.maps.Map($('#map')[0], myOptions);
var addresses = [<?php $numItems = count($val); $i=0; foreach($val as $data){ echo "['".$data['name']."','".$data['resp']."']"; if(++$i !== $numItems) {echo ",";}}?>];
//var colordot =[];
//alert(addresses);
for (var x = 0; x < addresses.length; x++) {
//alert(addresses[x][1]);
if (addresses[x][1] >= 50) {
var img= 'img/red-dot.png';
}
else{
var img= 'img/green-dot.png';
}
//alert(colordot[x]);
$.getJSON('http://maps.googleapis.com/maps/api/geocode/json?address='+addresses[x][0]+'&sensor=false', null, function (data) {
var p = data.results[0].geometry.location
var latlng = new google.maps.LatLng(p.lat, p.lng);
new google.maps.Marker({
icon: img,
position: latlng,
map: map
});
});
}
});
</script>
答案 0 :(得分:1)
解决问题的一种方法是在地理编码器调用中对img
变量进行函数闭包:
$.getJSON('http://maps.googleapis.com/maps/api/geocode/json?address=' + addresses[x][0] + '&sensor=false', null, function(img) {
return function(data) {
var p = data.results[0].geometry.location
var latlng = new google.maps.LatLng(p.lat, p.lng);
new google.maps.Marker({
icon: img,
position: latlng,
map: map
});
}
}(img));
代码段
$(document).ready(function() {
var map;
var elevator;
var myOptions = {
zoom: 4,
center: new google.maps.LatLng(39.639537564366684, -97.03125),
mapTypeId: 'terrain'
};
map = new google.maps.Map($('#map')[0], myOptions);
var addresses = [
["New York, NY", 1],
["Boston, MA", 75]
];
for (var x = 0; x < addresses.length; x++) {
if (addresses[x][1] >= 50) {
var img = 'http://maps.google.com/mapfiles/ms/micons/red.png';
} else {
var img = 'http://maps.google.com/mapfiles/ms/micons/green.png';
}
$.getJSON('http://maps.googleapis.com/maps/api/geocode/json?address=' + addresses[x][0] + '&sensor=false', null, function(img) {
return function(data) {
var p = data.results[0].geometry.location
var latlng = new google.maps.LatLng(p.lat, p.lng);
new google.maps.Marker({
icon: img,
position: latlng,
map: map
});
}
}(img)).fail(function(jqxhr, textStatus, error) {
var err = textStatus + ", " + error;
console.log("Request Failed: " + err);
});;
}
});
html,
body,
#map {
height: 100%;
width: 100%;
margin: 0px;
padding: 0px
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maps.googleapis.com/maps/api/js?libraries=geometry,places&ext=.js"></script>
<div id="map"></div>
答案 1 :(得分:0)
我遇到了类似的异步地理编码问题,我最终用bind()方法解决了这个问题。
你可以尝试:
var marker = new google.maps.Marker({
icon: img,
position: latlng,
map: map
});
$.getJSON('http://maps.googleapis.com/maps/api/geocode/json?address='+addresses[x][0]+'&sensor=false', null, function (data) {
var p = data.results[0].geometry.location
var latlng = new google.maps.LatLng(p.lat, p.lng);
this.position = latlng;
this.icon = img;
}.bind(marker));