Question

我试图将孩子附加到JSON中的相应父级... 以下是我的代码：我在$ json1中有一个json，在$ json2中有多个json。 $ json1和$ json2 - https://pastebin.com/DTn5EPxq

       <?php

        $djson1 = json_decode($json1);
        $djson2 = json_decode($json2, true);
        $result['id'] = $djson1->{'id'};
        $result['name'] = $djson1->{'name'};
        $result['tooltip'] = $djson1->{'tooltip'};
        $result['color'] = $djson1->{'color'};
        foreach ($djson1->{'children'} as $key => $value) {
            $result['children'][$key]['name'] = $value->{'name'};
                $result['children'][$key]['parent'] = $value->{'parent'};
            $result['children'][$key]['tooltip'] = $value->{'tooltip'};
            $result['children'][$key]['color'] = $value->{'color'};
        }
        foreach ($djson2 as $key2 => $value2) {
            if($value2['name'] == $result['children'][$key2]['name']) {
                foreach ($value2['children'] as $key3 => $value3) {
            $result['children'][$key2]['children']
            [$key3]['name'] = $value3['name'];
            $result['children'][$key2]['children']
            [$key3]['parent'] = $value3['parent'];
            $result['children'][$key2]['children']
            [$key3]['tooltip'] = $value3['tooltip'];
            $result['children'][$key2]['children']
            [$key3]['color'] = $value3['color'];
                }
            }
        }


        //var_dump($result);
        //var_dump(json_encode($result));

        ?>


        <?php echo json_encode($result,JSON_UNESCAPED_UNICODE); ?>

我在此行中收到未定义的偏移量错误：

        if($value2['name'] == $result['children'][$key2]['name']) {

这个代码效果很好，当我在$ json2中使用少量json时..显示错误只有在$ json2中使用大量json时才会解决这个问题???

Answer 1

因为$result['children'][2]['name']没有密钥2。它只有0和1所以它是未定义的索引

$ result数组

        $result = Array ( [id] => 1 
            [name] => à®•à¯à®´à¯‚à®‰ 
            [tooltip] => [color] => 
            [children] => Array ( [0] => Array ( [name] => à®•à¯‚à®Ÿà¯à®Ÿà®®à¯ [parent] => 1 [tooltip] => [color] => #FF0000 ) 
                                  [1] => Array ( [name] => [parent] => 1 [tooltip] => [color] => #FFFFCC )
                                )
            )

更新1：

使用array_column获取所有孩子的姓名并使用array_search如果匹配则返回密钥。所以使用该键可以像这样推送数组

$new_array = array_column($result['children'],'name');

    foreach ($djson2 as $key2 => $value2) {

        if($new_key = array_search($value2['name'],$new_array)) 
        {
            foreach ($value2['children'] as $key3 => $value3) 
            {
                $result['children'][$new_key]['children'][$key3]['name'] = $value3['name'];
                $result['children'][$new_key]['children'][$key3]['parent'] = $value3['parent'];
                $result['children'][$new_key]['children'][$key3]['tooltip'] = $value3['tooltip'];
                $result['children'][$new_key]['children'][$key3]['color'] = $value3['color'];
            }
        }
    }

更新2：

问题是我们的$json1 name is "கூட்டம் "有空格但$json2 name is "கூட்டம்"这就是为什么它不会进入if条件只是用户array_map来修剪这样的空间。

        $array1 = array_column($result['children'],'name');
       $new_array = array_map('trim',$array1);

        foreach ($djson2 as $key2 => $value2) {

            $true_or_false_key = array_search($value2['name'],$new_array);


            if($true_or_false_key !== false)
            {
                foreach ($value2['children'] as $key3 => $value3)
                {
                    $result['children'][ $true_or_false_key]['children'][$key3]['name'] = $value3['name'];
                    $result['children'][ $true_or_false_key]['children'][$key3]['parent'] = $value3['parent'];
                    $result['children'][ $true_or_false_key]['children'][$key3]['tooltip'] = $value3['tooltip'];
                    $result['children'][ $true_or_false_key]['children'][$key3]['color'] = $value3['color'];
                }
            }
        }

json子追加到相应的父级

1 个答案: