Question

我希望将肥皂消息转换成肥皂消息，使用mule中的xslt

我没有将肥皂消息1中的元素添加到肥皂消息2

1。我有肥皂

<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
<soapenv:Header>
<ns:topic xmlns:ns="http://wso2.org/ns/2009/09/eventing/notify">polling_Topic</ns:topic>
</soapenv:Header>
<soapenv:Body>

<data-services-event>

<service-name>pollingService</service-name>
<query-id>pollingQuery</query-id>
<time>Wed May 24 10:01:18 ICT 2017</time>

<content>
<Students xmlns="http://ws.wso2.org/dataservice/samples/eventing_sample">
<student>

<count>25</count>
<id>25</id>
<Name>Tran Anh</Name>
<Contact>Dong Thap</Contact>
<regdatetime>2017-05-23T14:41:35.000+07:00</regdatetime>

</student>
</Students>
</content>

</data-services-event>

</soapenv:Body>
</soapenv:Envelope>
</soap:Body>
</soap:Envelope>

这是transform.xsl

<?xml version="1.0" encoding="UTF-8"?>         
    <xsl:stylesheet version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>          
        <xsl:template match="/">
            <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"                                         xmlns:dat="http://dataservice.ws.wso2.org">
                      <soapenv:Header/>
                      <soapenv:Body>
                         <dat:insertPerson>
                            <!--Optional:--><dat:name><xsl:value-of select="soapenv:Envelope/soapenv:Body/data-services-event/content/Students/student/Name" /></dat:name>
                            <!--Optional:--><dat:contact><xsl:value-of select="data-services-event/content/Students/student/Contact/text()" /></dat:contact>

                         </dat:insertPerson>
                      </soapenv:Body>
             </soapenv:Envelope>    
        </xsl:template>
    </xsl:stylesheet>

我收到结果：

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
                  xmlns:dat="http://dataservice.ws.wso2.org"
                  xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
   <soapenv:Header/>
   <soapenv:Body>
      <dat:insertPerson>
         <dat:name/>
         <dat:contact/>         
      </dat:insertPerson>
   </soapenv:Body>
</soapenv:Envelope>

我没有得到元素：姓名和联系方式

怎么做

Answer 1

有两个原因导致您无法获得预期值。一个是你的路径缺少一些位置步骤。另一个是Students元素及其后代位于命名空间中，您需要使用绑定到同一命名空间的前缀来选择它们。

这是你的样式表，有一些修改：

XSLT 1.0

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:dat="http://dataservice.ws.wso2.org"
xmlns:stu="http://ws.wso2.org/dataservice/samples/eventing_sample"
exclude-result-prefixes="stu">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>          

<xsl:template match="/">
    <soapenv:Envelope >
        <soapenv:Header/>
        <soapenv:Body>
            <dat:insertPerson>
                <dat:name>
                    <xsl:value-of select="soapenv:Envelope/soapenv:Body/soapenv:Envelope/soapenv:Body/data-services-event/content/stu:Students/stu:student/stu:Name" />
                </dat:name>
                <dat:contact>
                    <xsl:value-of select="soapenv:Envelope/soapenv:Body/soapenv:Envelope/soapenv:Body/data-services-event/content/stu:Students/stu:student/stu:Contact" />
                </dat:contact>
            </dat:insertPerson>
        </soapenv:Body>
    </soapenv:Envelope>    
</xsl:template>

</xsl:stylesheet>

将肥皂消息转换为肥皂消息使用Mule中的xslt

1 个答案: