Question

我正在使用angularjs 1.6.4版本，我将我的密钥和值发送到php web服务但我的密钥和值没有读取，我得到的数据存储在＆＃39; 0＆＃39;，这是我的角度js代码，

        $scope.fav = {
            "userid":101,
            "favid":120
        }
        $http({
            method:"POST",
            url:apiurl+"addFavorites.php",
            data:JSON.stringify($scope.fav)
        }).then(function(data)
        {
            $scope.favorites = data.data;
            alert(data.data.message);
        });

这是我的php rest api

include("../includes/db.php");

//creating response array
$response = array();

$request_method = $_SERVER['REQUEST_METHOD'];
if ($request_method == 'POST' && array_key_exists('HTTP_X_HTTP_METHOD', $_SERVER)) {
    if ($_SERVER['HTTP_X_HTTP_METHOD'] == 'DELETE') {
      $request_method = 'DELETE';
    } else if ($_SERVER['HTTP_X_HTTP_METHOD'] == 'PUT') {
      $request_method = 'PUT';
    } else {
      throw new Exception("Unexpected Header");
    }
}

if($request_method == "POST"){

    //getting values
    $userid = isset($_POST['userid']) && $_POST['userid'] != '' ? trim($_POST['userid']) : "";
    $favid = isset($_POST['favid']) && $_POST['favid'] != '' ? trim($_POST['favid']) : "";

    if ($favid == 0) {
    $strupdate = mysql_query("insert into nr_favourites(UserProfileId,FavouriteUserProfileId,CreatedDate)Values('$userid','$favid',now())");
    }
    if ($favid != 0) {
        $sql = mysql_query("select * from nr_favourites where id=$favid");
        $rc = mysql_num_rows($sql);
        if ($rc != 0) {
            $strupdate = mysql_query("insert into nr_favourites(UserProfileId,FavouriteUserProfileId,CreatedDate)Values('$userid','$favid',now())");
        }
    }

    if ($strupdate) 
    {
        $response['error']=false;
        $response['message']='add favourites successfully!';
    }
    else
    {
        $response['error']=true;
        $response['message']='add favourites not successfully.';
    }

} else {
    $response['error']=true;
    $response['message']='You are not authorized';
}
header('Content-Type: application/json');
echo json_encode($response);

那些是我的代码，请帮我解决这个错误

Answer 1

看起来您可能正在将字符串保存到数字字段中。调用JSON.stringify($scope.fav)时，数字将转换为字符串。

这里

$userid = isset($_POST['userid']) && $_POST['userid'] != '' ? trim($_POST['userid']) : ""; $favid = isset($_POST['favid']) && $_POST['favid'] != '' ? trim($_POST['favid']) : "";

由于user_id和favid是字符串，因此每次都将它们设置为空字符串。我的猜测都是

nr_favourites.UserProfileId
nr_favourites.FavouriteUserProfileId

是接收字符串的数字字段，因此是0值。删除JSON.stringify（）并保存空字符而不是空字符串，这应该解决问题。

php web服务无法读取我的角度js键值

1 个答案: