如何使用jquery

时间:2017-05-24 04:59:10

标签: javascript php jquery css ajax

每日问候!!!

我在使用ajax URL传递参数时遇到问题。 我正在尝试使用jquery $ .ajax方法将多个数据发送到我的php脚本,但是当我连接多个数据时,我只能传递单个数据。 当我尝试更新另一个字段但该字段未更新并且第一个更新时。只有第一次现场更新。遗留字段不更新。我正面临更新其他字段的问题。我也尝试在ajax URL中传递多个参数但是收到错误。不更新任何字段。
请检查我的代码并给我解决方案。

我希望你们都明白。

谢谢!!!

这是我的代码:

<?php
include("connect.php");
?>
<!DOCTYPE html>
<html>
<head>
    <meta content="text/html; charset=utf-8" http-equiv="Content-Type">
    <meta charset="utf-8">
    <title>Editable Tables using jQuery - jQuery AJAX PHP</title>   
    <link href="assets/css/bootstrap.min.css" rel="stylesheet" type="text/css">
    <link href="assets/css/custom.css" rel="stylesheet" type="text/css">
</head>
<body>
    <div class="container">    
      <div style="text-align:center;width:100%;font-size:24px;margin-bottom:20px;color: #2875BB;">Click on the underlined words to edit them</div>
      <div class="row">
        <table class= "table table-striped table-bordered table-hover">
            <thead>
                <tr>
                    <th colspan="1" rowspan="1" style="width: 180px;" tabindex="0">FName</th>
                    <th colspan="1" rowspan="1" style="width: 220px;" tabindex="0">LName</th>
                    <th colspan="1" rowspan="1" style="width: 288px;" tabindex="0">Email</th>

                    <th colspan="1" rowspan="1" style="width: 288px;" tabindex="0">Gender</th>
                    <th colspan="1" rowspan="1" style="width: 288px;" tabindex="0">Address</th>
                    <th colspan="1" rowspan="1" style="width: 288px;" tabindex="0">City</th>
                    <th colspan="1" rowspan="1" style="width: 288px;" tabindex="0">Course</th>
                    <th colspan="1" rowspan="1" style="width: 288px;" tabindex="0">Hobby</th>
                </tr>
            </thead>

            <tbody>
                <?php
                $query = mysql_query("SELECT * FROM student_data");
                $i=0;
                while($fetch = mysql_fetch_array($query))
                {
                 if($i%2==0) $class = 'even'; else $class = 'odd';
                 echo'<tr class="'.$class.'">
                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['fname'].'</span></td>
                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['lname'].'</span></td>
                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['email'].'</span></td>

                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['gender'].'</span></td>
                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['address'].'</span></td>
                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['city'].'</span></td>
                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['course'].'</span></td>
                 <td><span class= "xedit" id="'.$fetch['id'].'">'.$fetch['hobby'].'</span></td>
             </tr>';                            
         }
         ?>
     </tbody>
 </table>
</div>
<script src="assets/js/jquery.min.js"></script> 
<script src="assets/js/bootstrap.min.js"></script>
<script src="assets/js/bootstrap-editable.js" type="text/javascript"></script> 
<script type="text/javascript">
    jQuery(document).ready(function() {  
        $.fn.editable.defaults.mode = 'popup';
        $('.xedit').editable();     
        $(document).on('click','.editable-submit',function(){
         var x = $(this).parents('td').children('span').attr('id');
         var y = $('.input-sm').val();
         var z = $(this).parents('td').children('span');
         alert(x);
         alert(y);
         alert(z);
         $.ajax({
            url:"process.php?id="+x+"&fname="+y,
            type: 'GET',
            success: function(s){
               if(s == 'city'){
                   $(z).html(y);}
                   if(s == 'error') {
                       alert('Error Processing your Request!');}
                   },
                   error: function(e){
                       alert('Error Processing your Request!!');
                   }
               });
     });
    });
</script>
</div>
</body>
</html>

这是我的另一个档案:

<?php
include("connect.php");
if($_GET['id'])
{
    $id = $_GET['id'];
    $fname = $_GET['fname'];
    $lname=$_GET['lname'];
    $email=$_GET['email'];

    $gender=$_GET['gender'];
    $address=$_GET['address'];
    $city=$_GET['city'];
    $course=$_GET['course'];
    $hobby = explode(',', $_GET['hobby']);
    if(mysql_query("UPDATE student_data SET fname='$fname', lname = '$lname', email = '$email', gender='$gender', address='$address', city='$city', course='$course', hobby='$hobby' where id='$id'"));
    echo 'success';
}
?>

这里是Ajax代码:

<script type="text/javascript">
    jQuery(document).ready(function() {  
        $.fn.editable.defaults.mode = 'popup';
        $('.xedit').editable();     
        $(document).on('click','.editable-submit',function(){
         var x = $(this).parents('td').children('span').attr('id');
         var y = $('.input-sm').val();
         var z = $(this).parents('td').children('span');
         alert(x);
         alert(y);
         alert(z);
         $.ajax({
            url:"process.php?id="+x+"&fname="+y,
            type: 'GET',
            success: function(s){
               if(s == 'city'){
                   $(z).html(y);}
                   if(s == 'error') {
                       alert('Error Processing your Request!');}
                   },
                   error: function(e){
                       alert('Error Processing your Request!!');
                   }
               });
     });
    });
</script>

enter image description here

2 个答案:

答案 0 :(得分:3)

问题在于:

csv

在这里,您只发送url:"process.php?id="+x+"&fname="+y, id,并在PHP脚本中尝试获取:

fname

ans这么多参数,这是错误的。

发送多个参数的正确方法是:

$id = $_GET['id'];
$fname = $_GET['fname'];
$lname=$_GET['lname'];

或通过在其中附加所有data: { key1: value1, key2: value2, key3: value3, and so on } key来格式化正确的网址,如:

value

答案 1 :(得分:2)

发送单个参数

data: "id="+id,

发送多个参数

data: {
    id: id,
    fname: fname
},