Question

Hy Master，我尝试在MVS ASP.net中创建CRUD，但是在构建和运行程序时遇到一个问题这是我的模型，EmployeeDB：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Data;
using System.Data.SqlClient;
using System.Configuration;

namespace CRUDAjax.Models
{
    public class EmployeeDB
    {
        //declare connection string
        string cs = ConfigurationManager.ConnectionStrings["DBCS"].ConnectionString;

        //Return list of all Employees
        public List<Employee> ListAll()
        {
            List<Employee> lst = new List<Employee>();
            using(SqlConnection con=new SqlConnection(cs))
            {
                con.Open();
                SqlCommand com = new SqlCommand("SelectEmployee",con);
                com.CommandType = CommandType.StoredProcedure;
                SqlDataReader rdr = com.ExecuteReader();
                while(rdr.Read())
                {
                    lst.Add(new Employee { 
                        EmployeeID=Convert.ToInt32(rdr["EmployeeId"]),
                        Name=rdr["Name"].ToString(),
                        Age = Convert.ToInt32(rdr["Age"]),
                        State = rdr["State"].ToString(),
                        Country = rdr["Country"].ToString(),
                    });
                }
                return lst;
            }
        }

        //Method for Adding an Employee
        public int Add(Employee emp)
        {
            int i;
            using(SqlConnection con=new SqlConnection(cs))
            {
                con.Open();
                SqlCommand com = new SqlCommand("InsertUpdateEmployee", con);
                com.CommandType = CommandType.StoredProcedure;
                com.Parameters.AddWithValue("@Id",emp.EmployeeID);
                com.Parameters.AddWithValue("@Name", emp.Name);
                com.Parameters.AddWithValue("@Age", emp.Age);
                com.Parameters.AddWithValue("@State", emp.State);
                com.Parameters.AddWithValue("@Country", emp.Country);
                com.Parameters.AddWithValue("@Action", "Insert");
                i = com.ExecuteNonQuery();
            }
            return i;
        }

        //Method for Updating Employee record
        public int Update(Employee emp)
        {
            int i;
            using (SqlConnection con = new SqlConnection(cs))
            {
                con.Open();
                SqlCommand com = new SqlCommand("InsertUpdateEmployee", con);
                com.CommandType = CommandType.StoredProcedure;
                com.Parameters.AddWithValue("@Id", emp.EmployeeID);
                com.Parameters.AddWithValue("@Name", emp.Name);
                com.Parameters.AddWithValue("@Age", emp.Age);
                com.Parameters.AddWithValue("@State", emp.State);
                com.Parameters.AddWithValue("@Country", emp.Country);
                com.Parameters.AddWithValue("@Action", "Update");
                i = com.ExecuteNonQuery();
            }
            return i;
        }

        //Method for Deleting an Employee
        public int Delete(int ID)
        {
            int i;
            using (SqlConnection con = new SqlConnection(cs))
            {
                con.Open();
                SqlCommand com = new SqlCommand("DeleteEmployee", con);
                com.CommandType = CommandType.StoredProcedure;
                com.Parameters.AddWithValue("@Id", ID);
                i = com.ExecuteNonQuery();
            }
            return i;
        }
    }
}

这是我的控制器HomeController：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using CRUDAjax.Models;

namespace CRUDAjax.Controllers
{
    public class HomeController : Controller
    {
        EmployeeDB empDB = new EmployeeDB();
        // GET: Home
        public ActionResult Index()
        {
            return View();
        }
        public JsonResult List()
        {
            return Json(empDB.ListAll(),JsonRequestBehavior.AllowGet);
        }
        public JsonResult Add(Employee emp)
        {
            return Json(empDB.Add(emp), JsonRequestBehavior.AllowGet);
        }
        public JsonResult GetbyID(int ID)
        {
            var Employee = empDB.ListAll().Find(x => x.EmployeeID.Equals(ID));
            return Json(Employee, JsonRequestBehavior.AllowGet);
        }
        public JsonResult Update(Employee emp)
        {
            return Json(empDB.Update(emp), JsonRequestBehavior.AllowGet);
        }
        public JsonResult Delete(int ID)
        {
            return Json(empDB.Delete(ID), JsonRequestBehavior.AllowGet);
        }
    }
}

这是erorr输出

System.NullReferenceException was unhandled by user code
  HResult=-2147467261
  Message=Object reference not set to an instance of an object.
  Source=CRUDAjax
  StackTrace:
       at CRUDAjax.Models.EmployeeDB..ctor() in c:\users\jujur\documents\visual studio 2015\Projects\CRUDAjax\CRUDAjax\Models\EmployeeDB.cs:line 15
       at CRUDAjax.Controllers.HomeController..ctor() in c:\users\jujur\documents\visual studio 2015\Projects\CRUDAjax\CRUDAjax\Controllers\HomeController.cs:line 12
  InnerException

： ScreenShot Erorr

Answer 1

在转换为整数或小数之前更好地检查是否有空值，否则在数据库ISNULL（@ Variable，0）中检查NULL值...选择是你的

Answer 2

未找到连接字符串，请仔细检查连接字符串是否存在。

string cs = ConfigurationManager.ConnectionStrings["DBCS"].ConnectionString;

ASP MVC，System.NullReferenceException未被用户代码处理

2 个答案: