我有这个数组...你怎么打印每个文件路径和文件名?这样做的最佳方式是什么?
Array (
[0] => Array (
[fid] => 14
[list] => 1
[data] => Array (
[alt] =>
[title] =>
)
[uid] => 1
[filename] => trucks_10785.jpg
[filepath] => sites/default/files/trucks_10785.jpg
[filemime] => image/jpeg
[filesize] => 143648
[status] => 1
[timestamp] => 1291424171
[nid] => 8
)
[1] => Array (
[fid] => 19
[list] => 1
[data] => Array (
[alt] =>
[title] =>
)
[uid] => 1
[filename] => school.jpg
[filepath] => sites/default/files/school.jpg
[filemime] => image/jpeg
[filesize] => 115355
[status] => 1
[timestamp] => 1292029563
[nid] => 8
)
[2] => Array (
[fid] => 20
[list] => 1
[data] => Array (
[alt] =>
[title] =>
)
[uid] => 1
[filename] => Life_is_wonderful_by_iNeedChemicalX.jpg
[filepath] => sites/default/files/Life_is_wonderful_by_iNeedChemicalX_0.jpg
[filemime] => image/jpeg
[filesize] => 82580
[status] => 1
[timestamp] => 1292029572
[nid] => 8
)
[3] => Array (
[fid] => 21
[list] => 1
[data] => Array (
[alt] =>
[title] =>
)
[uid] => 1
[filename] => school_rural.jpg
[filepath] => sites/default/files/school_rural.jpg
[filemime] => image/jpeg
[filesize] => 375088
[status] => 1
[timestamp] => 1292029582
[nid] => 8
)
)
答案 0 :(得分:180)
使用不带密钥的foreach
循环
foreach($array as $item) {
echo $item['filename'];
echo $item['filepath'];
// to know what's in $item
echo '<pre>'; var_dump($item);
}
使用带密钥的foreach
循环
foreach($array as $i => $item) {
echo $array[$i]['filename'];
echo $array[$i]['filepath'];
// $array[$i] is same as $item
}
使用for
循环
for ($i = 0; $i < count($array); $i++) {
echo $array[$i]['filename'];
echo $array[$i]['filepath'];
}
var_dump
是获取数组或对象快照的非常有用的函数。
答案 1 :(得分:6)
好的,我知道有一个已接受的答案但是...对于更多特殊情况,你也可以使用这个:
array_map(function($n) { echo $n['filename']; echo $n['filepath'];},$array);
或者以更复杂的方式:
function printItem($n){
echo $n['filename'];
echo $n['filepath'];
}
array_map('printItem', $array);
这将允许您以更简单的方式操作数据。
答案 2 :(得分:5)
从简单开始,没有HTML:
foreach($database as $file) {
echo $file['filename'] . ' at ' . $file['filepath'];
}
你可以操纵foreach中的字段。
答案 3 :(得分:1)
foreach($array as $item=>$values){
echo $values->filepath;
}
答案 4 :(得分:-1)
您也可以使用此方法而无需创建其他变量,也无需像foreach()那样将数据复制到内存中。
while (false !== (list($item, $values) = each($array)))
{
...
}