Java / Yahoo Finance检索报价，错误401

Question

这是我使用crumbs下载历史雅虎财务报价的Java代码。对不起，这不是最有效的代码。我还在学习Java。对我来说一切看起来都是正确的，但是在拿起面包屑并尝试第二次访问“https”// query1.finance.yahoo.com之后我得到错误401 ...“

我做错了什么想法？

    URL myUrl = null;
    try {
        myUrl = new URL("https://finance.yahoo.com");
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    URLConnection urlConn = null;
    try {
        urlConn = myUrl.openConnection();
    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    try {
        urlConn.connect();
    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    String headerName=null;
    String crumb = null;
    for (int i = 1; (headerName = urlConn.getHeaderFieldKey(i)) != null; i++) {
        if (headerName.equals("Set-Cookie")) {                  
            String cookie = urlConn.getHeaderField(i);

             cookie = cookie.substring(0, cookie.indexOf(";"));
             crumb = cookie.substring(cookie.indexOf("=") + 1, cookie.indexOf("&"));
            }
    }

    StringBuilder qUrl = new StringBuilder();
    qUrl.append("https://query1.finance.yahoo.com/v7/finance/download/AAPL");
    qUrl.append("?period1=" + 1495813803L);
    qUrl.append("&period2=" + 1497887408L);
    qUrl.append("&interval=1d");
    qUrl.append("&events=history");
    qUrl.append("&crumb=" + crumb);

    URL url = null;
    try {
        url = new URL(qUrl.toString());
    } catch (MalformedURLException e) {
        e.printStackTrace();
    }
    URLConnection conn;
    InputStream is = null;
    try {
        conn = url.openConnection();
        String redirect = conn.getHeaderField("Location");              // Can handle one redirection
        if(redirect != null ) {
            conn = new URL(redirect).openConnection();
        }
        is = conn.getInputStream();
    } catch (IOException e) {
        e.printStackTrace();
    }