我正在尝试使用PHP和MySQL中的数据库构建一个未提供的列表菜单树。
我有一个从数据库返回的页面对象数组。每个页面对象都有parent_id属性,如果它没有父属性,则设置为null。这是页面对象的样子:
page object
id
title
parent_id
如果可能的话,我不想以递归方式执行,只打了一次数据库,因为我将在几乎每个请求上构建菜单。我想创建一个函数,我可以将我的对象数组传递给它,它将返回html列表。
答案 0 :(得分:16)
我喜欢@ mario的解决方案,并通过防止多余的<ul>
对其进行了改进。我建议您在SQL查询上执行ORDER BY
以获得所需顺序的菜单(甚至可以建议将权重/序列列添加到模式中。
数据设置:
$menu = array( // Presumed to have been coming from a SQL SELECT, populated for demo.
array('id'=>1,'title'=>'Menu 1', 'parent_id'=>null),
array('id'=>2,'title'=>'Sub 1.1', 'parent_id'=>1),
array('id'=>3,'title'=>'Sub 1.2', 'parent_id'=>1),
array('id'=>4,'title'=>'Sub 1.3', 'parent_id'=>1),
array('id'=>5,'title'=>'Menu 2', 'parent_id'=>null),
array('id'=>6,'title'=>'Sub 2.1', 'parent_id'=>5),
array('id'=>7,'title'=>'Sub Sub 2.1.1', 'parent_id'=>6),
array('id'=>8,'title'=>'Sub 2.2', 'parent_id'=>5),
array('id'=>9,'title'=>'Menu 3', 'parent_id'=>null),
);
处理:
function has_children($rows,$id) {
foreach ($rows as $row) {
if ($row['parent_id'] == $id)
return true;
}
return false;
}
function build_menu($rows,$parent=0)
{
$result = "<ul>";
foreach ($rows as $row)
{
if ($row['parent_id'] == $parent){
$result.= "<li>{$row['title']}";
if (has_children($rows,$row['id']))
$result.= build_menu($rows,$row['id']);
$result.= "</li>";
}
}
$result.= "</ul>";
return $result;
}
echo build_menu($menu);
输出:
<ul>
<li>Menu 1<ul>
<li>Sub 1.1</li>
<li>Sub 1.2</li>
<li>Sub 1.3</li>
</ul></li>
<li>Menu 2<ul>
<li>Sub 2.1<ul>
<li>Sub Sub 2.1.1</li>
</ul></li>
<li>Sub 2.2</li>
</ul></li>
<li>Menu 3</li>
</ul>
答案 1 :(得分:3)
我最终选择了这个解决方案(pastebin reference):
<?php
/**
* Generate HTML for multi-dimensional menu from MySQL database
* with ONE QUERY and WITHOUT RECURSION
* @author J. Bruni
*/
class MenuBuilder
{
/**
* MySQL connection
*/
var $conn;
/**
* Menu items
*/
var $items = array();
/**
* HTML contents
*/
var $html = array();
/**
* Create MySQL connection
*/
function MenuBuilder()
{
$this->conn = mysql_connect( 'localhost', 'user', 'pass' );
mysql_select_db( 'example', $this->conn );
}
/**
* Perform MySQL query and return all results
*/
function fetch_assoc_all( $sql )
{
$result = mysql_query( $sql, $this->conn );
if ( !$result )
return false;
$assoc_all = array();
while( $fetch = mysql_fetch_assoc( $result ) )
$assoc_all[] = $fetch;
mysql_free_result( $result );
return $assoc_all;
}
/**
* Get all menu items from database
*/
function get_menu_items()
{
// Change the field names and the table name in the query below to match tour needs
$sql = 'SELECT id, parent_id, title, link, position FROM menu_item ORDER BY parent_id, position;';
return $this->fetch_assoc_all( $sql );
}
/**
* Build the HTML for the menu
*/
function get_menu_html( $root_id = 0 )
{
$this->html = array();
$this->items = $this->get_menu_items();
foreach ( $this->items as $item )
$children[$item['parent_id']][] = $item;
// loop will be false if the root has no children (i.e., an empty menu!)
$loop = !empty( $children[$root_id] );
// initializing $parent as the root
$parent = $root_id;
$parent_stack = array();
// HTML wrapper for the menu (open)
$this->html[] = '<ul>';
while ( $loop && ( ( $option = each( $children[$parent] ) ) || ( $parent > $root_id ) ) )
{
if ( $option === false )
{
$parent = array_pop( $parent_stack );
// HTML for menu item containing childrens (close)
$this->html[] = str_repeat( "\t", ( count( $parent_stack ) + 1 ) * 2 ) . '</ul>';
$this->html[] = str_repeat( "\t", ( count( $parent_stack ) + 1 ) * 2 - 1 ) . '</li>';
}
elseif ( !empty( $children[$option['value']['id']] ) )
{
$tab = str_repeat( "\t", ( count( $parent_stack ) + 1 ) * 2 - 1 );
// HTML for menu item containing childrens (open)
$this->html[] = sprintf(
'%1$s<li><a href="%2$s">%3$s</a>',
$tab, // %1$s = tabulation
$option['value']['link'], // %2$s = link (URL)
$option['value']['title'] // %3$s = title
);
$this->html[] = $tab . "\t" . '<ul class="submenu">';
array_push( $parent_stack, $option['value']['parent_id'] );
$parent = $option['value']['id'];
}
else
// HTML for menu item with no children (aka "leaf")
$this->html[] = sprintf(
'%1$s<li><a href="%2$s">%3$s</a></li>',
str_repeat( "\t", ( count( $parent_stack ) + 1 ) * 2 - 1 ), // %1$s = tabulation
$option['value']['link'], // %2$s = link (URL)
$option['value']['title'] // %3$s = title
);
}
// HTML wrapper for the menu (close)
$this->html[] = '</ul>';
return implode( "\r\n", $this->html );
}
}
示例数据:
CREATE TABLE `menu_item` (
`id` int(11) NOT NULL,
`title` varchar(75) DEFAULT NULL,
`link` varchar(100) DEFAULT NULL,
`parent_id` int(11) DEFAULT NULL,
`position` int(11) DEFAULT NULL,
PRIMARY KEY (`id`)
);
INSERT INTO `menu_item` (`id`, `title`, `link`, `parent_id`, `position`) VALUES (1,'1','1.html',0,1);
INSERT INTO `menu_item` (`id`, `title`, `link`, `parent_id`, `position`) VALUES (2,'2','2.html',0,2);
INSERT INTO `menu_item` (`id`, `title`, `link`, `parent_id`, `position`) VALUES (3,'11','11.html',1,1);
INSERT INTO `menu_item` (`id`, `title`, `link`, `parent_id`, `position`) VALUES (4,'12','12.html',1,2);
INSERT INTO `menu_item` (`id`, `title`, `link`, `parent_id`, `position`) VALUES (5,'21','21.html',2,1);
INSERT INTO `menu_item` (`id`, `title`, `link`, `parent_id`, `position`) VALUES (6,'22','22.html',2,2);
INSERT INTO `menu_item` (`id`, `title`, `link`, `parent_id`, `position`) VALUES (7,'3','3.html',0,3);
用法:
$menu = new MenuBuilder();
echo '<pre>' . htmlentities( $menu->get_menu_html() ) . '</pŕe>';
答案 2 :(得分:2)
不是递归地查询数据库,而是可以拉出所有条目并使输出函数递归。它通常很简单:
function print_list($array, $parent=0) {
print "<ul>";
foreach ($array as $row) {
if ($row->parent_id == $parent) {
print "<li>$row->title";
print_list($array, $row->id); # recurse
print "</li>";
} }
print "</ul>";
}
将<ul>
嵌套到<li>
中非常重要。或者只使用HTML并忽略结束</li>
。
实际上打印的<ul>
太多了,所以我会检查是否存在子级别并避免直接打印。