Question

我有list的{{1}}：

dicts

如果只有1名得分最高的玩家，我可以回答该玩家没问题：

>>> for player in players:
    print(player.show_hand())

'{'name': 'Tim', 'hand': [Card(rank='7', suit='diamonds', value=6), Card(rank='9', suit='spades', value=8)], 'score': 1}
 {'name': 'Manu', 'hand': [Card(rank='9', suit='clubs', value=8), Card(rank='7', suit='clubs', value=6)], 'score': 1}
 {'name': 'Kawhi', 'hand': [Card(rank='K', suit='diamonds', value=12), Card(rank='2', suit='clubs', value=1)], 'score': 1}
 {'name': 'Tony', 'hand': [Card(rank='Q', suit='clubs', value=11), Card(rank='3', suit='clubs', value=2)], 'score': 1}'

如果有相同分数的玩家因为他们拥有相同类型的牌（例如最高牌），我想迭代列表并检查每个score_list = [] for num in range(len(players)): score_list.append(players[num].show_hand()['score']) winner = [] for player in players: if player.show_hand()['score'] == max(score_list): winner.append(player.show_hand()['name']) if len(winner) > 1: print('draw') highest_card = [] for player in players: if player.show_hand()['name'] in winner: print(player.show_hand()['name']) for num in range(2): highest_card.append(player.show_hand()['hand'][num].value) for num in range(2): if player.show_hand()['hand'][num].value == max(highest_card): print('The Winner is ', player.show_hand()['name']) print(highest_card) else: print('The Winner is ', winner)的{{1}}玩家最高hand list以确定获胜者或游戏是否为平局。这是我失败的地方。

编辑：

当所有玩家Card为1（最高牌）或2（对）时，这是我得到的输出：

value

卡是一个名为元组：

score

Answer 1

我通过向key highest_card_value中的player个实例添加新的players list来解决此问题。然后，我比较value中Card个hand个对象，并给出highest_card_value手中最高牌的值。

for player in players:
    player.show_hand()['score'] = score.define_score(player.show_hand()['hand'] + dealer.show_hand())
    if player.show_hand()['hand'][0].value > player.show_hand()['hand'][1].value:
        player.show_hand()['highest_card_value'] = player.show_hand()['hand'][0].value
    else:
        player.show_hand()['highest_card_value'] = player.show_hand()['hand'][1].value

然后循环遍历值：

score_list = []
for num in range(len(players)):
    score_list.append(players[num].show_hand()['score'])

winner = []
for player in players:
    if player.show_hand()['score'] == max(score_list):
        winner.append(player.show_hand()['name'])
print(winner)

if len(winner) > 1:
    print('draw')
    highest_card = []
    for player in players:
        if player.show_hand()['name'] in winner:
            for num in range(2):
                highest_card.append(player.show_hand()['hand'][num].value)
    for player in players:
        if player.show_hand()['highest_card_value'] == max(highest_card):
            print('The Winner is ', player.show_hand()['name'])
    print(max(highest_card))

else:
    print('The Winner is ', winner)

这是输出：

{'hand': [Card(rank='3', suit='spades', value=2), Card(rank='2', suit='diamonds', value=1)], 'name': 'Tim', 'highest_card_value': 2, 'score': 1}
{'hand': [Card(rank='Q', suit='clubs', value=11), Card(rank='7', suit='diamonds', value=6)], 'name': 'Manu', 'highest_card_value': 11, 'score': 1}
{'hand': [Card(rank='6', suit='hearts', value=5), Card(rank='A', suit='spades', value=13)], 'name': 'Kawhi', 'highest_card_value': 13, 'score': 1}
{'hand': [Card(rank='3', suit='diamonds', value=2), Card(rank='2', suit='clubs', value=1)], 'name': 'Tony', 'highest_card_value': 2, 'score': 1}
['Tim', 'Manu', 'Kawhi', 'Tony']
draw
The Winner is  Kawhi
13

每张牌都有最高牌hand，但是Kawhi牌的价值最高，所以他赢了。

Python - 如何从值列表中的值本身的字典列表中返回最高值？

1 个答案: