Question

问题是获取<md-input-container [hideRequiredMarker]="true">

每天的结果百分比

status = '404 NOT FOUND'

查询结果

SELECT CAST(time AS DATE) as day, status, count(*),
        count(*) * 100.0 / (
            SELECT count(*) FROM log
            GROUP BY CAST(time AS DATE)
            HAVING CAST(time AS DATE) = '2016-07-17'
        ) as percent 
FROM log L
GROUP BY day, status
HAVING status = '404 NOT FOUND'
ORDER BY percent DESC

我不想让day | status | count | percent --------------------------------------------------------------- 2016-07-17 | 404 NOT FOUND | 1267 | 2.2650481792016018 2016-07-24 | 404 NOT FOUND | 429 | 0.76693422957970574039 2016-07-05 | 404 NOT FOUND | 425 | 0.75978332767220265656 2016-07-19 | 404 NOT FOUND | 422 | 0.75442015124157534369 2016-07-21 | 404 NOT FOUND | 419 | 0.74905697481094803082 2016-07-08 | 404 NOT FOUND | 416 | 0.74369379838032071795 2016-07-06 | 404 NOT FOUND | 414 | 0.74011834742656917604 2016-07-09 | 404 NOT FOUND | 410 | 0.73296744551906609221硬编码，而是想在外部查询中传递2016-07-17的值，即day

像这样：

L.day

这样做

SELECT CAST(time AS DATE) as day, status, count(*),
        count(*) * 100.0 / (
            SELECT count(*)FROM log
            GROUP BY CAST(time AS DATE)
            HAVING CAST(time AS DATE) = L.day
        ) as percent 
FROM log L
GROUP BY day, status
HAVING status = '404 NOT FOUND'
ORDER BY percent DESC

更新：根据评论

ERROR:  column l.day does not exist
LINE 5:    HAVING CAST(time AS DATE) = L.day
                                       ^

同样的结果。

Answer 1

您无法在定义的同一级别访问别名，您需要使用= cast(l.time as date)。

但是那个条款并没有真正意义 - 至少对我而言

我认为你想要的是：

SELECT CAST(time AS DATE) as day, 
       status, 
       count(*),
       count(*) * 100.0 / (SELECT count(*)
                           FROM log l2
                           where cast(l2.time as date) = CAST(l.time AS DATE)) as percent 
FROM log L
GROUP BY day, status
HAVING status = '404 NOT FOUND'
ORDER BY percent DESC;

在线示例：http://rextester.com/SYJV63284

Postgres：传递行值以选择子查询

1 个答案: