我想从表td调用javascript函数并将此td值作为此javascript函数的参数传递。这是我的剧本和表格。
<table width="100%" class="track">
<tr>
<th colspan="2">Load Information</th>
</tr>
<tr>
<td>LOAD DATE:</td>
<td id="ldate"><?php echo $datas[0]->DATE?> </td>
</tr>
</table>
<script>
function formatDate(date_string) {
var date = new Date(date_string);
var monthNames = [
"January", "February", "March",
"April", "May", "June", "July",
"August", "September", "October",
"November", "December"
];
var day = date.getDate();
var monthIndex = date.getMonth();
var year = date.getFullYear();
if (day < 10) {
day = '0' + day;
}
return monthNames[monthIndex] + ' ' + day + ', ' + year ;
}
</script>
我希望显示类似MARCH 03,2016的日期格式,但我的实际格式将显示为2016-03-03。
答案 0 :(得分:1)
使用PHP {/ 1}}和strtotime()
:
date()