Question

我需要获得最后10个元素或10分钟和array.count。在Objective-C中，我这样做了：

Objective-C代码：

NSRange endRange = NSMakeRange(sortedArray.count >= 10 ? sortedArray.count - 10 : 0, MIN(sortedArray.count, 10));
NSArray *lastElements= [sortedArray subarrayWithRange:endRange];

在Swift中我做到了：

let endRange = NSMakeRange(values.count >= 10 ? values.count - 10 : 0, min(values.count , 10) )

但是不知道如何在swift中使用这个范围来获取数组。任何帮助，将不胜感激。感谢。

Answer 1

您可以使用数组实例方法suffix(_:)。请注意，使用后缀不需要检查数组计数。从数组末尾开始最多需要10个元素。

let array = Array(1...100)   // [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100]

let lastTenElements = Array(array.suffix(10))   // [91, 92, 93, 94, 95, 96, 97, 98, 99, 100]

Answer 2

您可以通过声明Range：

来获取它

let letters = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n"]

let desiredRange = letters.index(letters.endIndex, offsetBy: -10) ..< letters.endIndex

// ["e", "f", "g", "h", "i", "j", "k", "l", "m", "n"]
let lastTenLetters = (desiredRange.count > letters.count) ? letters : Array(letters[desiredRange])

请注意，如果所需范围的计数大于主数组的计数，则最后十个元素应该是整个主数组。

虽然我仍然同意Leo's answer适合您的情况，但我想提一下，这个解决方案的好处在于它不仅适用于最后一个元素，而且要清楚，考虑你希望在第一个元素之后获得10个元素（引用letters数组，元素应该是 bk ），通过实现所需的范围，你可以实现这一点，如下所示：

let letters = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n"]

let desiredRange = letters.index(letters.startIndex, offsetBy: 1) ..< letters.index(letters.startIndex, offsetBy: 11)

// ["b", "c", "d", "e", "f", "g", "h", "i", "j", "k"]
let lastTenLetters = (desiredRange.count > letters.count) ? letters : Array(letters[desiredRange])

Answer 3

var值：NSArray = [1,2,3,4,5,6,7,8,9,10,11]

    values = values.reversed() as NSArray

    let tenDigits = values.prefix(10)

    debugPrint(values.count >= 10 ? NSArray(array: (Array(tenDigits))) : min(values.count , 10))

从数组中获取最后10个元素：NSMakeRange

3 个答案: