Question

我使用Java中的Simple XML反序列化数据，但我得到一个例外告诉我：

protokolsimulering.model.Terminal.<init>()

这是我的序列化代码：

public void saveSimulationState(String simulationFile) {
    try{
        Strategy strategy = new CycleStrategy("id", "ref");
        Serializer serializer = new Persister(strategy);
        File result = new File(simulationFile);
        serializer.write(this.sm, result);
    }
    catch(Exception ex)
    {
        System.out.println(ex.getMessage());
    }
}

public void loadSimulationState(String simulationFile) {
    try {
        Strategy strategy = new CycleStrategy("id", "ref");
        Serializer serializer = new Persister(strategy);
        File source = new File(simulationFile);
        this.sm = serializer.read(Simulation.class, source);
    } catch (Exception ex) {
        System.out.println(ex.getLocalizedMessage());
    }
}

Terminal.java的代码是：

package protokolsimulering.model;

import java.util.ArrayList;
import protokolsimulering.model.DataPacket.*;

public class Terminal extends Sensor {

    public Terminal(int x, int y, double r) {
        super(x,y,r);
        learnPosition();
    }

    @Override
    public void init() {
        this.broadcast(PacketFactory.newRutePacket(this,0));
    }

    @Override
    public void step() {
        ArrayList<AbstractPacket> packetsThisStep = (ArrayList<AbstractPacket>) this.getPackages();

        for(AbstractPacket p : packetsThisStep) {
            if(p instanceof HalloPacket) {    
                // Rutningsprotokol
                send(p.getSender(),PacketFactory.newRutePacket(this,0));

                // Lokaliseringsprotokol
                send(p.getSender(), PacketFactory.newHerPacket(this, this.getKnownPosition()));
        }
    }
}

}

整个源代码可在以下网址找到：

http://code.google.com/p/sensor-protocol-simulation/source/browse/#svn/trunk/src/protokolsimulering

Answer 1

异常意味着问题与调用Terminal构造函数有关。

通常，要在反序列化时构造对象，必须使用no-args构造函数，如下所示：

public Terminal() {
    ...
}

使用简单XML反序列化时出现未知异常

1 个答案: