如何使用struts2在jsp中播放多个视频

时间:2017-05-23 06:01:42

标签: jsp video struts2

大家好我曾尝试在jsp页面播放视频,并获得成功。如何在jsp中播放多个视频,视频文件在特定文件夹中(文件系统) 下面是显示一个视频文件的代码

JSP

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
 <video width="400" controls>
 <source src="<s:url value="videoStream" />" type="video/mp4"/>
  <source src="mov_bbb.ogg" type="video/ogg">
  Your browser does not support HTML5 video.
</video>
</body>
</html>

**struts.xml**

<struts>
    <package name="user" namespace="/" extends="struts-default">
        <action name="videoStream" class="com.pradeep.videostream.VideoStreamingAction">
            <result name="success" type="stream">
                <param name="contentType">${yourContentType}</param>
                <param name="inputName">inputStream</param>
                <param name="contentDisposition">attachment;filename="${yourFileName}"</param>
                <param name="bufferSize">1024</param>
            </result>
        </action>
    </package>
</struts>

动作类

public class VideoStreamingAction extends ActionSupport {
    private InputStream inputStream;
     private String yourContentType;

        // getters and setters 

 public String execute() throws Exception {
           yourContentType = "video/mp4";
           File file =new File("D://svn videos//Create Java Spring Web MVC Project With Maven [EDITED].mp4");
           setInputStream(new ByteArrayInputStream(FileUtils.readFileToByteArray(file)));   
           return SUCCESS;
        }
}

我这样改变了我的jsp

<html>
<body>
<form action="getFiles">
<input type="submit" value="check">
</form>
<s:iterator value="filesList">
     <video width="400" controls>    
      <source src="<s:url value='getFiles.action?fileName='/><s:property/>" type="video/mp4" />     
      <source src="mov_bbb.ogg" type="video/ogg"> Your browser does not support HTML5 video. </video> 
</s:iterator>
</body>
</html>

struts.xml中

<struts>
    <package name="user" namespace="/" extends="struts-default">

    <action name="getFiles" class="com.pradeep.videostream.VideoStreamingAction">   
    <result name="success">index.jsp</result>   
    </action>

        <!-- <action name="videoStream" class="com.pradeep.videostream.VideoStreamingAction">
            <result name="success" type="stream">
                <param name="contentType">${yourContentType}</param>
                <param name="inputName">inputStream</param>
                <param name="contentDisposition">attachment;filename="${yourFileName}"</param>
                <param name="bufferSize">1024</param>
            </result>
        </action> -->
    </package>
</struts>

动作类

public class VideoStreamingAction extends ActionSupport {

    private static final long serialVersionUID = 1L;
    private InputStream inputStream;
    private String yourContentType;
    private File[] filesArray = null;
    private List<String> filesList = new ArrayList<String>();

//getters and setters

    public String execute() throws Exception {


        File folder = new File("D://svn videos");
        filesArray = folder.listFiles();
        for (int i = 0; i < filesArray.length; i++) {
            String fileName=filesArray[i].getName();
            filesList.add(fileName);
        }

        HttpServletResponse response = ServletActionContext.getResponse();
        HttpServletRequest request = ServletActionContext.getRequest();
        String fileName = request.getParameter("fileName");
        System.out.println("GGGGGGGGGGGGGGGGG "+fileName);

         File file = new File(fileName); 
        setInputStream(new ByteArrayInputStream(FileUtils.readFileToByteArray(file)));
        return SUCCESS;
    }
}

1 个答案:

答案 0 :(得分:0)

如果您想播放多个视频,则需要多个视频流。

由于操作的Stream结果代表一个流,因此您需要多个操作。

例如,您可以对不同的操作进行多次AJAX调用,或者将相同的操作传递给您要作为参数播放的文件的名称...但我不明白为什么你应该想玩一次多个视频。我们有两只眼睛和一只大脑,而且在多任务处理时真的太棒了......所以问题还不清楚。