在分隔符

Question

我有一个字符串需要在分隔符之间给出一个空格，例如：

Oceans and lakes have much in common,but they are also quite different.

预期输出应如下：

Oceans and lakes have much in common , but they are also quite different .

我尝试过preg_replace，我只能在下一个char中给出一个空格。

这是我的代码：

$string = "Oceans and lakes have much in common,but they are also quite different." $string = preg_replace('/([\.,\?\!\:])/',"\\1 ",$string);

输出：

Oceans and lakes have much in common, but they are also quite different.

非常感谢任何帮助。

Answer 1

尝试preg_replace('/([\.\?\!\:])/'\ \,\ \"\\1 ",$string);不确定php但是在bash中你必须逃避空格。

Answer 2

在替换（第二个参数）

中的\\1引用之前放置一个空格

$string = preg_replace('/([\.,\?\!\:])/'," \\1 ",$string);