Question

目标是查看两列之间的差异，每列包含相同的行条目，只是在不同的行上;

[
["ENSCAFG00000008901","ENSCAFG00000013762"],
["ENSCAFG00000029470","ENSCAFG00000003029"],
["ENSCAFG00000013782","ENSCAFG00000007249"],
["ENSCAFG00000000806","ENSCAFG00000012468"],
["ENSCAFG00000013341","ENSCAFG00000018167"],
["ENSCAFG00000003376","ENSCAFG00000003376"],
["ENSCAFG00000000812","ENSCAFG00000018164"],
["ENSCAFG00000012468","ENSCAFG00000001591"],
["ENSCAFG00000031786","ENSCAFG00000013782"],
["ENSCAFG00000000803","ENSCAFG00000030793"],
["ENSCAFG00000003029","ENSCAFG00000015177"],
["ENSCAFG00000011565","ENSCAFG00000005750"]
]

这个列表有更多行，所以我不能手工完成。例如，我们在第一列的第11行和第二列的第2行看到ENSCAFG00000003029。我想创建一些输出，显示第一列和第二列之间相对于第一列的行变化。所以在ENSCAFG00000003029的情况下，我想在ENSCAFG00000003029出现在第一列的行之后看到+9（或类似的东西）。

我希望我的目标很明确，这是提出问题的正确位置。

Answer 1

对于很长的列表来说它不会有效，但这应该有效：

lst = [
    ["ENSCAFG00000008901","ENSCAFG00000013762"],
    ["ENSCAFG00000029470","ENSCAFG00000003029"],
    ["ENSCAFG00000013782","ENSCAFG00000007249"],
    ["ENSCAFG00000000806","ENSCAFG00000012468"],
    ["ENSCAFG00000013341","ENSCAFG00000018167"],
    ["ENSCAFG00000003376","ENSCAFG00000003376"],
    ["ENSCAFG00000000812","ENSCAFG00000018164"],
    ["ENSCAFG00000012468","ENSCAFG00000001591"],
    ["ENSCAFG00000031786","ENSCAFG00000013782"],
    ["ENSCAFG00000000803","ENSCAFG00000030793"],
    ["ENSCAFG00000003029","ENSCAFG00000015177"],
    ["ENSCAFG00000011565","ENSCAFG00000005750"]
    ]

col_1 = [x[0] for x in lst]
col_2 = [x[1] for x in lst]

idx_offset = [None] * len(col_1)
for col_1_idx, val_1 in enumerate(col_1):
    try:
        col_2_idx = col_2.index(val_1)
    except ValueError:
        continue
    idx_offset[col_1_idx] = col_2_idx - col_1_idx

简而言之，对于第一列中的每个值，在第二列中找到相同值的索引（如果存在）。获取此索引，并从中扣除第一列中值的索引，以及您的输出。对于第一列中不会出现在第二列中的元素，输出（idx_offset）将为None。在这种情况下，输出将变为：

[None, None, 6, None, None, 0, None, -4, None, None, -9, None]

Answer 2

我认为你必须经过两次。例如，如果您简化假设第一列中的条目是唯一的，则可以执行以下操作：

cols = [['ENSCAFG00000008901', 'ENSCAFG00000013762'],
        ['ENSCAFG00000029470', 'ENSCAFG00000003029'],
        ['ENSCAFG00000013782', 'ENSCAFG00000007249'],
        ['ENSCAFG00000000806', 'ENSCAFG00000012468'],
        ['ENSCAFG00000013341', 'ENSCAFG00000018167'],
        ['ENSCAFG00000003376', 'ENSCAFG00000003376'],
        ['ENSCAFG00000000812', 'ENSCAFG00000018164'],
        ['ENSCAFG00000012468', 'ENSCAFG00000001591'],
        ['ENSCAFG00000031786', 'ENSCAFG00000013782'],
        ['ENSCAFG00000000803', 'ENSCAFG00000030793'],
        ['ENSCAFG00000003029', 'ENSCAFG00000015177'],
        ['ENSCAFG00000011565', 'ENSCAFG00000005750']]
positions = dict((x[0], i) for i, x in enumerate(cols))
[positions[x[1]]-i for i, x in enumerate(cols) if x[1] in positions]

输出：

[9, 4, 0, -6]

Answer 3

l1 =[]
l2 =[]
for item in cols:
    l1.append(item[0])
    l2.append(item[0])
for item in l1:
    if item in l2:
        print str(l2.index(item)) + ':'  + str(item)

Python：创建输出，显示两列

3 个答案: