表A的hbm.xml文件,其MyClass中的pojo类
<class name="com.entities.MyClass" table="A" entity-name="tableOne">
<id name="id" access="field" type="java.lang.Long">
<column name="ID" />
<generator class="increment" />
</id>
<property name="columnOne" type="java.lang.String">
<column name="COLUMN_ONE" />
</property>
<property name="columnTwo" type="java.lang.String">
<column name="COLUMN_TWO" />
</property>
</class>
表B的hbm.xml文件(它也有相同的pojo类“MyClass”)
<class name="com.entities.MyClass" table="B" entity-name="tableTwo">
<id name="id" access="field" type="java.lang.Long">
<column name="ID" />
<generator class="increment" />
</id>
<property name="columnOne" type="java.lang.String">
<column name="COLUMN_ONE" />
</property>
<property name="columnTwo" type="java.lang.String">
<column name="COLUMN_TWO" />
</property>
</class>
这是POJO类
package com.entities;
public class MyClass{
Long id;
String columnOne;
String columnTwo;
public MyClass() {
// TODO Auto-generated constructor stub
}
public MyClass(Long id, String columnOne, String columnTwo) {
super();
this.id = id;
this.columnOne = columnOne;
this.columnTwo = columnTwo;
}
/**
* @return the id
*/
public Long getId() {
return id;
}
/**
* @param id the id to set
*/
public void setId(Long id) {
this.id = id;
}
/**
* @return the columnOne
*/
public String getColumnOne() {
return columnOne;
}
/**
* @param columnOne the columnOne to set
*/
public void setColumnOne(String columnOne) {
this.columnOne = columnOne;
}
/**
* @return the columnTwo
*/
public String getColumnTwo() {
return columnTwo;
}
/**
* @param columnTwo the columnTwo to set
*/
public void setColumnTwo(String columnTwo) {
this.columnTwo = columnTwo;
}
}
如何插入表格?我尝试了以下代码:
session.save("tableOne",myClassObj);
transaction.commit();
但在提交时会抛出以下异常
Hibernate: select max(ID) from A
org.hibernate.MappingException: Unknown entity: com.entities.MyClass
答案 0 :(得分:0)
您可以按表格使用如下
session.save("A",myClassObj);
transaction.commit();