NSMutableDictionary *dict = [NSMutableDictionary dictionaryWithDictionary:@{@"Name": self.txt1.text , @"Roll No.":self.txt2.text,}];
NSMutableDictionary *dict1= [NSMutableDictionary dictionaryWithDictionary:@{@"Name":self.txt3.text , @"Roll No.":self.txt4.text}];
NSMutableDictionary *dict2 = [NSMutableDictionary dictionaryWithDictionary:@{@"Name":self.txt5.text , @"Roll No.":self.txt6.text}];
NSMutableDictionary *dict3 = [NSMutableDictionary dictionaryWithDictionary:@{@"Name":self.txt7.text, @"Roll No.":self.txt8.text}];
如何在单个数组中添加这些字典...
答案 0 :(得分:1)
在数组中添加对象(字典),如下所示: -
NSArray *arrayData = [[NSArray alloc]initWithObjects:dict,dict1,dict2,dict3, nil];
//在其他视图控制器中显示值(根据注释)NSDictionary: -
遍历数组,获取值,显示标签中的值(IBOutlets)
*dicData = [arrayData objectAtIndex:0];
NSString *name = [dicData objectForKey:@"Name"];
NSString *rollNo = [dicData objectForKey:@"Roll No."];
labelName.text = name;
labelRollNo.text = rollNo;
答案 1 :(得分:0)
attributes = [[NSMutableArray alloc] init];
[attributes addObject: dict.mutableCopy];
[attributes addObject: dict1.mutableCopy];
[attributes addObject: dict2.mutableCopy];
[attributes addObject: dict3.mutableCopy];
就是这样
答案 2 :(得分:0)
试试这个
NSMutableArray *arrDict = [NSMutableArray alloc]initWithObjects:@{@"Name" : self.txt1.text , @"Roll No" : self.txt2.text},@{@"Name" : self.txt7.text, @"Roll No" : self.txt8.text} nil
使用NSArray Literal
NSArray *arrDict =@[@{@"Name" : self.txt1.text , @"Roll No" : self.txt2.text},@{@"Name" : self.txt7.text, @"Roll No" : self.txt8.text} ];
在Next ViewController中,您可以通过循环
获取此词典for (NSDictionary *dicUser in arrDict) {
// this dictionary which contained by arrDict
UILabel *lblName = [dicUser objectForKey:@"Name"];
UILabel *lblRollNumber = [dicUser objectForKey:@"Roll No"];
}