Question

所以我在JSP的表格中有一个从mysql显示的电影及其信息列表。每部电影的表格条目都类似于<a id="135006" onmouseover=ajaxFunction(this); href=SearchSingleMovieServlet?txt_movie_id=135006>The Life Aquatic</a>。

我的ajax功能如下：

<script language="javascript" type="text/javascript">

function ajaxFunction(obj){
var ajaxRequest;  

try{
    // Opera 8.0+, Firefox, Safari
    ajaxRequest = new XMLHttpRequest();
} catch (e){
    // Internet Explorer Browsers
    try{
        ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
    } catch (e) {
        try{
            ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
        } catch (e){
            // Something went wrong
            alert("Your browser broke!");
            return false;
        }
    }
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
    if(ajaxRequest.readyState == 4){
        $( '#'+ obj.id ).tooltip({
             content: "<strong>Hi!</strong>",
             track:true
         });

         document.getElementById('popup').innerHTML = '#' + obj.id+ ajaxRequest.responseText;
    }
}
var parameter = "movie_id=" + obj.id;
ajaxRequest.open("POST","MoviePopUpWindowServlet", true);
ajaxRequest.setRequestHeader("Content-type"
        , "application/x-www-form-urlencoded") 
ajaxRequest.send(parameter);
}


</script>

行document.getElementById('popup').innerHTML = '#' + obj.id+ ajaxRequest.responseText;只是一个调试行，所以我可以看到代码是否进入AJAX函数并确保responseText正确显示（它确实如此）。但是，当我尝试将鼠标悬停在电影的链接上时，它的工具提示并没有显示出来。有什么理由吗？

jquery工具提示不从ajax函数显示

0 个答案: