Question

PHP错误：绑定变量数与令牌数不匹配。

我在这里缺少什么？我正在尝试为我的med应用程序添加新用户。

public function register($uname,$umail,$upass,$fname,$llastname)
{
    try
    {
        $new_password = password_hash($upass, PASSWORD_DEFAULT);

        $stmt = $this->conn->prepare("INSERT INTO users(name, lastname, user_name, user_email, user_pass) VALUES(:fname, :llastname, :uname, :umail, :upass)");
        $stmt->bindparam(":fname", $fname);
        $stmt->bindparam(":llastname", $llastname);
        $stmt->bindparam(":uname", $uname);
        $stmt->bindparam(":umail", $umail);
        $stmt->bindparam(":upass", $new_password);                                        

        $stmt->execute();   

        return $stmt;   
    }
    catch(PDOException $e)
    {
        echo $e->getMessage();
    }               
}


public function doLogin($uname,$umail,$upass)
{
    try
    {
        $stmt = $this->conn->prepare("SELECT name, lastname, user_id, user_name, user_email, user_pass FROM users WHERE name=:fname, lastname=:llastname, user_name=:uname OR user_email=:umail ");
        $stmt->execute(array(':uname'=>$uname, ':umail'=>$umail));
        $userRow=$stmt->fetch(PDO::FETCH_ASSOC);
        if($stmt->rowCount() == 1)
        {
            if(password_verify($upass, $userRow['user_pass']))
            {
                $_SESSION['user_session'] = $userRow['user_id'];
                return true;
            }
            else
            {
                return false;
            }
        }
    }
    catch(PDOException $e)
    {
        //HTTPS 
        echo $e->getMessage();
    }
}

addUser.php我绑错了吗？

$uname = strip_tags($_POST['txt_uname']);
$umail = strip_tags($_POST['txt_umail']);
$upass = strip_tags($_POST['txt_upass']);   
$fname = strip_tags($_POST['txt_fname']);
$llastname = strip_tags($_POST['txt_llastname']);

Answer 1

下面：

AADSTS70001: Application with identifier 'd340f0ed-5eb3-43e8-9a50-c449649f3ee1' was not found in the directory <MY_TEST_TENANT>

您使用4个（4个！）参数：$stmt = $user->runQuery("SELECT name, lastname, user_name,user_email FROM users WHERE name=:fname, lastname=:llastname, user_name=:uname OR user_email=:umail");，:fname，:llastname，:uname

然后，在执行它时，你只能绑定2（两个）参数：

:umail

这正是您收到错误的原因。

顺便提一下，你的SQL查询是错误的。您应该使用$stmt->execute(array(':uname' => $uname, ':umail' => $umail));加入,条件，而不是AND（逗号）。像这样：

WHERE

虽然，我不完全确定那里的AND和OR，你可能需要使用parantheses来实现你需要的逻辑

PHP参数号无效：

1 个答案: