Question

我有一个名为25600501.html的html文件

示例文件名

-25600501.html

-25600502.html

-25600503.html

-25600504.html

-25600505.html

我想阅读一个html文件循环。

with open(r'C:/Users/bac/Desktop/WORK/PYTHON/25600501.html', "r") as f:
    page = f.read()
root = LH.fromstring(page)

谢谢

Answer 1

您可以尝试使用glob.iglob循环文件目录C:/Users/bac/Desktop/WORK/PYTHON/中的所有html文件，如下所示：

import glob
for filename in glob.iglob('C:/Users/bac/Desktop/WORK/PYTHON/*.html'): #it will loop all your html files in the dir C:/Users/bac/Desktop/WORK/PYTHON/
    with open(filename) as f:
        page = f.read()

如何阅读html文件（循环）

1 个答案: