如何在响应网格中制作固定列?

时间:2017-05-21 20:52:11

标签: html css bootstrap-4

使用Bootstrap,是否可以为某些断点保持网格列固定? 并且为同一列堆叠并与其他断点的页面一起流动?

在下面的示例中,对于大屏幕,我希望右列中的内容在左列保持固定时滚动。对于小屏幕,左栏应叠加在右侧,页面应正常滚动。

<div class="container-fluid">
  <div class="row">
    <div class="col-lg-2">
      I want this to always be visible as the right side scrolls.
    </div>
    <div class="col">
    ...
    </div>
  </div>
</div>

CodePen sample

1 个答案:

答案 0 :(得分:4)

偏移未修复的列:

<div class="container-fluid">
  <div class="row">
    <div class="col-lg-2">
      I want this to always be visible as the right side scrolls.
    </div>
    <div class="col offset-lg-2">
    ...
    </div>
  </div>
</div>

并应用媒体查询来修复相关断点的其他列:

https://getbootstrap.com/docs/4.0/layout/grid/#grid-options https://getbootstrap.com/docs/4.0/layout/grid/#mixins

@include media-breakpoint-up('lg') {
    #left {
        position: fixed;
        top: 0;
        bottom: 0;
    }
}

Codepen sample