当我点击 - &gt;时,如何使用MVC C#和ajax复制以下表单? <input type="submit" value="Add another form" class="btn btn-default" />
例如,如果我点击一个按钮5次,我想要生成5个表单。
我希望用户添加更多客户端,而不是通过插入客户端信息来循环,然后再次使用相同的过程提交。
表格重复 - &gt;
@using (Html.BeginForm())
{
@Html.AntiForgeryToken()
<div class="form-horizontal">
<hr />
@Html.ValidationSummary(true, "", new { @class = "text-danger" })
{
<div class="form-group">
@Html.LabelFor(model => model.Title, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Title, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Title, "", new { @class = "text-danger" })
</div>
</div>
<div class="form-group">
@Html.LabelFor(model => model.Name, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Name, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Name, "", new { @class = "text-danger" })
</div>
</div>
<div class="form-group">
@Html.LabelFor(model => model.Phone_Number, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Phone_Number, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Phone_Number, "", new { @class = "text-danger" })
</div>
</div>
<div class="form-group">
@Html.LabelFor(model => model.Address, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Address, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Address, "", new { @class = "text-danger" })
</div>
</div>
<div class="form-group">
@Html.LabelFor(model => model.Email, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Email, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Email, "", new { @class = "text-danger" })
</div>
</div>
<hr />
<br />
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
答案 0 :(得分:1)
使用lazy val logger = ....
和.clone()
的jquery。您还需要更改输入的ID。
.append()
var inputIndex = 1;
$('.add').click(function(){
inputIndex = inputIndex + 1;
var inputIndexStr = inputIndex.toString();
var inputClone = $('.inputDiv:first-child').clone();
$(inputClone).find('input').val('').attr('id','input' + inputIndexStr + '');
$('form').append(inputClone);
});
.add{
color: red;
cursor: pointer;
}