Question

我有pandas'DataFrame，看起来像这样：

# Output 
#        A     B     C     D
# 0    3.0   6.0   7.0   4.0
# 1   42.0  44.0   1.0   3.0
# 2    4.0   2.0   3.0  62.0
# 3   90.0  83.0  53.0  23.0
# 4   22.0  23.0  24.0   NaN
# 5    5.0   2.0   5.0  34.0
# 6    NaN   NaN   NaN   NaN
# 7    NaN   NaN   NaN   NaN
# 8    2.0  12.0  65.0   1.0
# 9    5.0   7.0  32.0   7.0
# 10   2.0  13.0   6.0  12.0
# 11   NaN   NaN   NaN   NaN
# 12  23.0   NaN  23.0  34.0
# 13  61.0   NaN  63.0   3.0
# 14  32.0  43.0  12.0  76.0
# 15  24.0   2.0  34.0   2.0

我想要做的是用最早的前一行的B值填充NaN。除了列D之外，在这一行中，我希望将NaN替换为零。

我已经调查了ffill，fillna ..似乎无法完成这项工作。

到目前为止我的解决方案：

def fix_abc(row, column, df):

    # If the row/column value is null/nan 
    if pd.isnull( row[column] ):

        # Get the value of row[column] from the row before
        prior = row.name
        value = df[prior-1:prior]['B'].values[0]

        # If that values empty, go to the row before that
        while pd.isnull( value ) and prior >= 1 :
            prior = prior - 1
            value = df[prior-1:prior]['B'].values[0]

    else:
        value = row[column]

    return value 

df['A'] = df.apply( lambda x: fix_abc(x,'A',df), axis=1 )
df['B'] = df.apply( lambda x: fix_abc(x,'B',df), axis=1 )
df['C'] = df.apply( lambda x: fix_abc(x,'C',df), axis=1 )


def fix_d(x):
    if pd.isnull(x['D']):
        return 0
    return x

df['D'] = df.apply( lambda x: fix_d(x), axis=1 )

感觉这样效率很低，速度慢。所以我想知道是否有更快，更有效的方法来做到这一点。

示例输出;

#        A     B     C     D
# 0    3.0   6.0   7.0   3.0
# 1   42.0  44.0   1.0  42.0
# 2    4.0   2.0   3.0   4.0
# 3   90.0  83.0  53.0  90.0
# 4   22.0  23.0  24.0   0.0
# 5    5.0   2.0   5.0   5.0
# 6    2.0   2.0   2.0   0.0
# 7    2.0   2.0   2.0   0.0
# 8    2.0  12.0  65.0   2.0
# 9    5.0   7.0  32.0   5.0
# 10   2.0  13.0   6.0   2.0
# 11  13.0  13.0  13.0   0.0
# 12  23.0  13.0  23.0  23.0
# 13  61.0  13.0  63.0  61.0
# 14  32.0  43.0  12.0  32.0
# 15  24.0   2.0  34.0  24.0

我已将包含数据帧数据的代码转储到可用的python小提琴中（here）

Answer 1

fillna允许各种方式进行填充。在这种情况下，列D可以填充0。列B可以通过pad填写。然后，A和C列可以填充B列，例如：

<强>代码：

df['D'] = df.D.fillna(0)
df['B'] = df.B.fillna(method='pad')
df['A'] = df.A.fillna(df['B'])
df['C'] = df.C.fillna(df['B'])

测试代码：

df = pd.read_fwf(StringIO(u"""
       A     B     C     D
     3.0   6.0   7.0   4.0
    42.0  44.0   1.0   3.0
     4.0   2.0   3.0  62.0
    90.0  83.0  53.0  23.0
    22.0  23.0  24.0   NaN
     5.0   2.0   5.0  34.0
     NaN   NaN   NaN   NaN
     NaN   NaN   NaN   NaN
     2.0  12.0  65.0   1.0
     5.0   7.0  32.0   7.0
     2.0  13.0   6.0  12.0
     NaN   NaN   NaN   NaN
    23.0   NaN  23.0  34.0
    61.0   NaN  63.0   3.0
    32.0  43.0  12.0  76.0
    24.0   2.0  34.0   2.0"""), header=1)

print(df)

df['D'] = df.D.fillna(0)
df['B'] = df.B.fillna(method='pad')
df['A'] = df.A.fillna(df['B'])
df['C'] = df.C.fillna(df['B'])
print(df)

<强>结果：

       A     B     C     D
0    3.0   6.0   7.0   4.0
1   42.0  44.0   1.0   3.0
2    4.0   2.0   3.0  62.0
3   90.0  83.0  53.0  23.0
4   22.0  23.0  24.0   NaN
5    5.0   2.0   5.0  34.0
6    NaN   NaN   NaN   NaN
7    NaN   NaN   NaN   NaN
8    2.0  12.0  65.0   1.0
9    5.0   7.0  32.0   7.0
10   2.0  13.0   6.0  12.0
11   NaN   NaN   NaN   NaN
12  23.0   NaN  23.0  34.0
13  61.0   NaN  63.0   3.0
14  32.0  43.0  12.0  76.0
15  24.0   2.0  34.0   2.0

       A     B     C     D
0    3.0   6.0   7.0   4.0
1   42.0  44.0   1.0   3.0
2    4.0   2.0   3.0  62.0
3   90.0  83.0  53.0  23.0
4   22.0  23.0  24.0   0.0
5    5.0   2.0   5.0  34.0
6    2.0   2.0   2.0   0.0
7    2.0   2.0   2.0   0.0
8    2.0  12.0  65.0   1.0
9    5.0   7.0  32.0   7.0
10   2.0  13.0   6.0  12.0
11  13.0  13.0  13.0   0.0
12  23.0  13.0  23.0  34.0
13  61.0  13.0  63.0   3.0
14  32.0  43.0  12.0  76.0
15  24.0   2.0  34.0   2.0

从前一行＆amp;中有效地更新熊猫数据帧中的NaN。特定列值

1 个答案: