所以我试图从每一列中获取唯一值。到目前为止,我已经尝试过了。
日:周一,周二,周三,周四,周五
时间:上午8-10点,晚上10-12点,下午1-3点,下午3-5点,下午5-7点
SELECT DISTINCT Day, Time FROM table GROUP BY Day, Time;
实施例
Monday 8-10am
Monday 3-5pm
Monday 5-7pm
Tuesday 10-12pm
Tuesday 5-7pm
Wednesday 3-5pm
Thursday 10-12pm
Thursday 1-3pm
Friday 8-10am
Friday 1-3pm
这不会给我每列的唯一值,但是每天的每个TIME的唯一值。
SELECT
(SELECT group_concat(DISTINCT Day) FROM workingTimeDate) as Day,
(SELECT group_concat(DISTINCT Time) FROM workingTimeDate) as Time
FROM workingTimeDate;
这会给:
Monday,Tuesday,Wednesday,Thursday,Friday 8-10am,10-12pm,1-3pm,3-5pm,5-7pm
这会将值组合成两列,但我希望它们位于不同的列中。
我想要的是
Day Time
Monday 8-10am
Tuesday 10-12pm
Wednesday 1-3pm
Thursday 3-5pm
Friday 5-7pm
答案 0 :(得分:1)
你可以这样做:
select distinct day, cast(NULL as time) from t
union all
select distinct cast(NULL as date), time from t;
答案 1 :(得分:0)
所以你想要的是:
select Day,
group_concat(time, ', ') as t
FROM table
GROUP BY Day