Question

我想在Expressive中使用FastRoute的路由组。像样品：

$router = $app->getContainer()->get(FastRoute\RouteCollector::class);

$router->get('/', App\Action\HomePageAction::class);

$router->addGroup('/pages', function (FastRoute\RouteCollector $router) {
    $router->get('', App\Action\PagesIndexAction::class);
    $router->get('/add', App\Action\PagesAddAction::class);
    $router->get('/edit/{id}', App\Action\PageEditActionFactory::class);
    $router->post('/edit/{id}', App\Action\PageEditActionFactory::class);
    $router->get('/another/{section}[/{subsection}]', PagesAnotherActionFactory::class);  
});

我在docs（https://docs.zendframework.com/zend-expressive/features/router/fast-route/#advanced-configuration）中创建了工厂并在router.global.php：

中注册

// ...
'factories' => [
    FastRoute\RouteCollector::class => App\Container\FastRouteCollectorFactory::class,
    FastRoute\DispatcherFactory::class => App\Container\FastRouteDispatcherFactory::class,
    Zend\Expressive\Router\RouterInterface::class => App\Container\RouterFactory::class,
],
// ...

现在我无法弄清楚在哪里编写配置以及如何激活它。可以在文件config/router.php中完成吗？请帮帮我。

Answer 1

只要文件与配置的其余部分合并，您就可以将它们放在'dependencies' => [ //.. 'invokables' => [ /* ... */ // Comment out or remove the following line: // Zend\Expressive\Router\RouterInterface::class => Zend\Expressive\Router\FastRouteRouter::class, /* ... */ ], 'factories' => [ /* ... */ // Add this line; the specified factory now creates the router instance: FastRoute\RouteCollector::class => App\Container\FastRouteCollectorFactory::class, FastRoute\DispatcherFactory::class => App\Container\FastRouteDispatcherFactory::class, // Zend\Expressive\Router\RouterInterface::class => Zend\Expressive\Router\FastRouteRouterFactory::class, // replaced by following line Zend\Expressive\Router\RouterInterface::class => App\Container\RouterFactory::class, /* ... */ ], ],中。

dependencies

请注意RouterFactory密钥，并且您自己的FastRouteRouterFactory会替换joined_layer=QgsVectorLayer(path,name,"ogr") intersected_layer=QgsVectorLayer(path,name,"ogr") featuresJ=joined_layer.getFeatures() featuresI=intersected_layer.getFeatures() featuresB=Bld_layer.getFeatures() for fJ in featuresJ: for fI in featuresI: geomI=fI.geometry() #lo piglia for fB in featuresB: geomB=fB.geometry() if geomI.area()*2>=geomB.area(): val= fI[1] else: val= fJ[2] print val，因为它共享相同的配置密钥。

Answer 2

不支持，我不确定是否可以在FastRoute中实现。

您可以查看主题＆＃34; Zend router - child routes＆＃34;

Zend Expressive中的FastRoute组

2 个答案: