如何从Python 3.6.0中的另一个函数中的另一个文件访问函数内部的已修改类变量？

Question

正在修改的类：

class Player:
    def __init__(self, name):
        self.name = name
        self.maxhealth = 100
        self.health = self.maxhealth
        self.maxmp = 20
        self.mp = self.maxmp
        self.fireres = 0.1
        self.thunderres = 0.01
        self.totalattack = 15
        self.basedefense = 20
        self.blooddrops = 50
        self.pots = 1
        self.allmagic = ["fireball", "t-phase"]
        self.usemagic = ""
        self.armor = ["dirt rag"]
        self.curarmor = "naked"
        self.weapon = ["snapped sword"]
        self.curweapon = "fist" 
    @property
    def defense(self):
        defense = self.basedefense

        if self.curarmor == "naked":
            defense += 0
            self.fireres += .1
        if self.curarmor == "dirt rag":
            defense += 5
            self.fireres += .1
        if self.curarmor == "leather armor":
            defense += 10

        if self.curarmor == "metal armor":
            defense += 20

        return defense

    @property
    def attack(self):
        attack = self.totalattack

        if self.curweapon == "snapped sword":
            attack += 5

        if self.curweapon == "greatsword":
            attack += 15

        if self.curweapon == "sword":
            attack += 7

        if self.curweapon == "fist":
            attack += 0

        return attack

File1中：

import sys
import os
import time
import random
from File1 import name


name()

1. File1转到File2

文件2：

import sys
import os
import time
import random
from abc import ABCMeta, abstractmethod
from File3 import start1
from Classes_Player import Player

def name():
    clear = lambda: os.system('cls')
    print("Have you got a name lad!?")
    option2 = input("Type (Yes or No):").lower()
    if option2 == "yes" or option2 == "y":
        print("Ah, brilliant!")
        time.sleep(1)
        print("What be it?")
        option = input("Type:")
        global PlayerIG
        PlayerIG = Player(option)
        if len(option) >= 20:
            print("shorten it a bit please, for brevity")
            time.sleep(2)
            clear()
            name()
        elif len(option) == 0:
            print("Lad that's not a name, that's emptiness")
            time.sleep(2)
            clear()
            name()
        else:
            print("Are you sure? (Yes or No)")
            ans = input().lower()
            if ans == "yes" or ans == "y":
               print("Alrighty then, just wanted to be sure lad.")
               time.sleep(2)
               start1()

1. 它在这里做的是修改Player类，并将其转换为类的name变量是用户的输入（我相信）。然后转到File3

文件3

import sys
import os
import time
import random
from abc import ABCMeta, abstractmethod
from Intro import *


def start1():
    clear = lambda: os.system('cls')
    clear()
    print("Name: {}".format(PlayerIG.name))
    print("Health: {}/{}".format(PlayerIG.health, PlayerIG.maxhealth))
    print("Attack: {}".format(PlayerIG.attack))
    print("Defense: {}".format(PlayerIG.defense))
    print("Mana: {}/{}".format(PlayerIG.mp, PlayerIG.maxmp))
    print("Equipped Armor: {}".format(PlayerIG.curarmor))
    print("Equipped Weapon: {}".format(PlayerIG.curweapon))
    print("Healing potions: {}".format(PlayerIG.pots))
    print("Wealth: {}\n".format(PlayerIG.blooddrops))
    print("1.) Inventory")
    print("2.) Check Player")
    print("3.) Save")
    print("4.) Fight")
    print("5.) Shop")
    print("6.) Exit")
    ans = input().lower()
    if ans == "inventory" or ans == "i" or ans == "1":
        inventory()
    elif ans == "check player" or ans == "cp" or ans == "check" or ans == "c" or ans == "2":
        status()
    elif ans == "save" or ans == "s" or ans == "3":
        clear()
    elif ans == "exit" or ans == "e" or ans == "6":
        exit
    elif ans == "fight" or ans == "f" or ans == "4":
        prefight()
    elif ans == "shop" or ans == "s" or ans == "5":
        shop_keeper()
    else:
        start1()

1. 我在这里收到错误"NameError: name 'PlayerIG' is not defined"，我已经查了一下，但是对于这个实例的帮助没有占上风。任何帮助表示赞赏。