如何将此访问代码写入sqlite代码

Question

选择Person.Person_id，Person.name，Person.last_name，（从债务中选择sum（debt.paye），其中debt.person_id = Person.Person_id）AS sum_pay，（从信用债务中选择总和（debt.not_paye）） .person_id = Person.Person_id）AS sum_not_pay， [sum_pay] - [sum_non_pay] AS def 来自人;

Answer 1

select Person.Person_id, Person.name, Person.last_name,sum_pay,sum_non_pay, sum_pay-sum_non_pay as def 
from 
(
SELECT Person.Person_id, Person.name, Person.last_name, ( select sum(credit.paye) from credit where credit.person_id= Person.Person_id) AS sum_pay, ( select sum(credit.non_paye) from credit where credit.person_id= Person.Person_id) AS sum_non_pay
from person
)