Question

我想在文本字段中打印file_get_contents()返回值。

我的表单（input.html）：

<form name="" action="form.php" method="post">
    <input type="text" name="number" id="number"/>
    <input type="submit" name="submit" value="go"/>
</form>

这是我想要绑定的视图页面（form.php）

<?php 
$number = $_REQUEST['number'];
echo $number;
$data = file_get_contents('http://apis.sdsds.sds/api/Get_Loadsheet_Details/'.$number);
?>

以下是file_get_contents()返回值：

[{"ID":103,"FROM_ID":1,"NAME":"CUTTACK","COMPANY_NAME":"B K TRADING","CMP_ID":8473,"LR_NO":"00107","LR_ID":752,"LMID":17,"TO_ID":4,"DESTINATION":"TALCHER","GODAWN_ID":1,"GODAWN":"BAJARKABATI ROAD","NO_OF_PKT":8.00,"TOPAY_AMOUNT":0.00,"REMARKS":"","LOADIG_STATUS":"Close","LR_STATUS":"Delivered","LOADING_SHEETNO":"00006","MANUAL_LOADSHEET_NO":"","modeof_payment":"PAID","COLLECTED_TOPAY_AMNT":0.00,"LOADFROMMST":"CUTTACK","LOADFROMMSTID":1,"DESTINATION_ID":4,"LOADDESTINATIONNAME":"TALCHER","SUFIX":"BK","MST_GODAWN":1,"GODAWNMASTER":"BAJARKABATI ROAD","LRGODAWN":"BAJARKABATI ROAD","LRSUFIX":"BK","LRGODAWNID":1,"VEHICLE_NO":"OD-05-N-3856","VEHICLEID":799,"basic_freight":320.00,"sur_charge":0.00,"hamali":16.00,"lr_charge":30.00,"service_charge":0.00,"cover_charge":0.00,"dd_charge":0.00,"dp_charge":0.00,"grand_total":366.00,"booking_incharge":"SURYA","clubpoint":0.00,"onloading_charge":0.00,"LOADSHEET_TYPE":"NORMAL","DATE":"2017-04-03T00:00:00","lrConfirmStatus":null,"lrLoadStatus":null}]

我想在bind.php的文本字段中绑定此返回值，这是我的绑定代码：

<input type="text" name="cmpname" value="<?php echo $data[0].COMPANY_NAME?>"/>

但是它显示了警告信息，我认为在上面的文本字段中绑定有些错误。

Answer 1

首先，你需要json_decode你的文字。

$data = json_decode($data);

您应该可以使用以下行正确访问您的值

<input type="text" name="cmpname" value="<?php echo $data[0]->COMPANY_NAME?>"/>

请注意，我替换了“。”用“ - ＆gt;” 在php中，点表示连接。

Answer 2

假设您有一个json文件。通过这种方式你可以操作它，我已经将json文件保存在languages文件夹中。

<suite name="Cryptography" verbose="1" parallel="classes" thread-count="8">

，因为html表单是

<?php


if(isset($_POST['number'])){

$number = $_POST['number'];

$counter=0;
$mydata=0;

$data = file_get_contents('languages/en.json');

$d = json_decode($data);

    foreach ($d as $key) {

        if($counter+1==$number){

            $mydata=$key;
        }

        $counter++;
    }

}

?>
<!DOCTYPE html>
<html>
<head>

<meta charset="utf-8">
<title>JSON example</title>

</head>
<body>
<input type="text" name="cmpname" value="<?php $mydata ?>" placeholder="<?= $mydata ?>">



</body>
</html>

在你的例子中，你从.html转移到form.php，你想把结果放到第三个文件（bind.php），你可以留在第二个.php文件

如何绑定file_get_contents（）返回文本字段中的值

2 个答案: