Question

我在delphi中翻译了两个函数，但我不知道它们是否正确，我需要编写Queue以了解我是否正确。

这是我在delphi中写的：

def do_aes_encrypt(key2_t_xor)

这是原始的python代码：

function key_transform (old_key:string): string;
var
x :integer;
 begin
result:='';
for x := 32 downto 0 do
result:= result + chr(ord(old_key[x-1])-( x mod $0C)) ;
end;


function key_xoring ( key2_t :string ; kilo_challenge :string) : string ;
var
i :integer;
begin
result := '';
i:=0 ;
while i <= 28 do begin
result := result + chr(ord(key2_t[i+1]) xor ord(kilo_challenge[3]));
result := result + chr(ord(key2_t[i+2]) xor ord(kilo_challenge[2])) ;
result := result+ chr(ord(key2_t[i+3]) xor ord (kilo_challenge[1])) ;
i := i + 4 ;
end;
end;

此代码用于计算数据行16字节作为32字节的附加发送
前看起来照片蓝色的标记线是我需要通过在porple中标记的4字节十六进制来计算的这是关键 key2 ='qndiakxxuiemdklseqid~a~niq，zjuxl'

在德尔福因为python代码工作正常

look to the photo

如何运作

当我收到KILOCENT ANSOWER作为照片展示时，这是为LG电话升级固件

def key_transform(old_key):
        new_key = ''
        for x in range(32,0,-1):
        new_key += chr(ord(old_key[x-1]) - (x % 0x0C))
        return new_key

    def key_xoring(key2_t, kilo_challenge):
        key2_t_xor = ''
        i = 0
        while i <= 28:
            key2_t_xor += chr(ord(key2_t[i]) ^ ord(kilo_challenge[3]))
        key2_t_xor += chr(ord(key2_t[i+1]) ^ ord(kilo_challenge[2]))
        key2_t_xor += chr(ord(key2_t[i+2]) ^ ord(kilo_challenge[1]))
        key2_t_xor += chr(ord(key2_t[i+3]) ^ ord(kilo_challenge[0]))
        i = i + 4
        return key2_t_xor

    def do_aes_encrypt(key2_t_xor):
        plaintext = b''
        for k in range(0,16):
            plaintext += chr(k)
        obj = AES.new(key2_t_xor, AES.MODE_ECB)
        return obj.encrypt(plaintext)



/////////////////////////////////////////////////////////////////////////////           
            {
            kilo_challenge = kilo_header[8:12]
            chalstring = ":".join("{:02x}".format(ord(k)) for k in kilo_challenge)  
            key2 = 'qndiakxxuiemdklseqid~a~niq,zjuxl' # if this doesnt work try 'lgowvqnltpvtgogwswqn~n~mtjjjqxro'
            kilo_response = do_aes_encrypt(key_xoring(key_transform(key2),kilo_challenge))}

我必须发送KILOMETER REQUEST手机第一线和第二线固定没有变化，但第三条我必须通过AES ECB MODE加密外观改变它

     this below change every time phone connected
                               ||  
                               V
4b 49 4c 4f 43 45 4e 54 ([ac e5 b1 06]) 00 00 00 00   KILOCENT¬å±.....
00 00 00 00 00 00 00 00 30 d4 00 00 b4 b6 b3 b0   ........0Ô..´¶³°

这是旧密钥

4b 49 4c 4f 4d 45 54 52 00 00 00 00 02 00 00 00   KILOMETR........ 
00 00 00 00 10 00 00 00 85 b6 00 00 b4 b6 b3 b0   ........…¶..´¶³° 
fc 21 d8 e5 5b aa fd 58 1e 33 58 fd e9 0b 65 38   ü!Øå[ªýX.3Xýé.e8 <==this

在delphi AES MODE ECB中编写python代码

0 个答案: