我知道为了跳过http请求中的标题信息，您需要使用//Student.h
#ifndef STUDENT_H
#define STUDENT_H
#include <string>
class Student {
public:
Student(const char * const name, int perm);
int getPerm() const;
const char * const getName() const;
void setPerm(const int perm);
void setName(const char * const name);
Student(const Student &orig);
~Student();
Student & operator=(const Student &right);
std::string toString() const;
private:
int perm;
char *name; // allocated on heap
};
#endif
//studentRoll.h
#ifndef STUDENTROLL_H
#define STUDENTROLL_H
#include <string>
#include "student.h"
class StudentRoll {
public:
StudentRoll();
void insertAtTail(const Student &s);
std::string toString() const;
StudentRoll(const StudentRoll &orig);
~StudentRoll();
StudentRoll & operator=(const StudentRoll &right);
private:
struct Node {
Student *s;
Node *next;
};
Node *head;
Node *tail;
};
#endif
//studentRoll.cpp
#include <string>
#include "studentRoll.h"
#include <sstream>
#include <iostream>
StudentRoll::StudentRoll() {
head = tail = NULL;
}
void StudentRoll::insertAtTail(const Student &s) {
/* tail -> next = new Node;
tail = tail -> next;
tail -> s = s;
tail -> next = null;
*/
Node* n = new Node;
n -> s = new Student(s);
n -> next = NULL;
if (head == NULL){
head = n;
}
if(tail != NULL){
tail -> next = n;
}
n -> next = NULL;
tail = n;
}
std::string StudentRoll::toString() const {
std::ostringstream oss;
oss << "[";
Node *p = head;
while (p){
oss << p -> s -> toString();
if(p != tail) oss << ",";
p = p -> next;
}
oss << "]";
delete p;
return oss.str();
}
StudentRoll::StudentRoll(const StudentRoll &orig) {
Node *p1 = 0;
Node *p2 = 0;
if (orig.head == NULL){
head = NULL;
tail = NULL;
}
else{
head = new Node;
head -> s = new Student(*(orig.head -> s));
std::cout << "got here";
p1 = head;
p2 = orig.head -> next;
}
while(p2){
p1 -> next = new Node;
p1 = p1 -> next;
p1 -> s = new Student(*(orig.head -> s));
p2 = p2 -> next;
}
p1 -> next = NULL;
tail = p1;
delete p1;
delete p2;
}
StudentRoll::~StudentRoll() {
Node *current = head;
while ( current != 0 ){
Node* next = current->next;
delete current;
current = next;
}
}
StudentRoll & StudentRoll::operator =(const StudentRoll &right ) {
// The next two lines are standard, and you should keep them.
// They avoid problems with self-assignment where you might free up
// memory before you copy from it. (e.g. x = x)
if (&right == this)
return (*this);
// TODO... Here is where there is code missing that you need to
// fill in...
Node *p1 = 0;
Node *p2 = 0;
if (right.head == NULL){
head = NULL;
tail = NULL;
}
else{
head = new Node;
head -> s = new Student(*(right.head -> s));
p1 = head;
p2 = right.head -> next;
}
while(p2){
p1 -> next = new Node;
p1 = p1 -> next;
p1 -> s = new Student(*(p2 -> s));
p2 = p2 -> next;
}
p1 -> next = NULL;
tail = p1;
delete p1;
delete p2;
// KEEP THE CODE BELOW THIS LINE
// Overloaded = should end with this line, despite what the textbook says.
return (*this);
}
。我已经阅读了一些有关此问题的问题/主题，但没有任何实现对我有用。为简单起见，我将使用没有相对路径的URL（硬编码GET命令）。
我使用的网址是\r\n，我知道它的IP地址是elf.cs.pub.ro。此示例的超简化代码如下：
141.85.227.116问题出在#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <unistd.h>
#include <sys/types.h>
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#include <errno.h>
#define MAXLEN 500
void send_command(int sockfd, char sendbuf[], char * expected) {
char recvbuf[MAXLEN];
if(send(sockfd, sendbuf, strlen(sendbuf), 0) > 0) {
int data = recv(sockfd, recvbuf, MAXLEN - 1, 0);
printf("%s\n", recvbuf);
if(strstr(recvbuf, expected) == NULL) {
exit(0);
}
}
}
int main(int argc, char * * argv) {
int sockfd;
struct sockaddr_in servaddr;
char server_ip[20] = "141.85.227.116";
char sendbuf[MAXLEN];
char recvbuf[MAXLEN];
if ((sockfd = socket(AF_INET, SOCK_STREAM, 0)) < 0) {
printf("Socket creation error.\n");
exit(-1);
}
memset( & servaddr, 0, sizeof(servaddr));
servaddr.sin_family = AF_INET;
servaddr.sin_port = htons(80);
if (inet_aton(server_ip, & servaddr.sin_addr) <= 0) {
printf("Invalid IP\n");
exit(-1);
}
if (connect(sockfd, (struct sockaddr * ) & servaddr, sizeof(servaddr)) < 0) {
printf("Connection error\n");
exit(-1);
}
//If I use "GET / HTTP1.0\r\n" the connection never ends
//and same for "GET / HTTP1.0"...
sprintf(sendbuf,"GET / HTTP/1.0\r\n\r\n");
char expected[MAXLEN];
strcpy(expected, "2");
send_command(sockfd, sendbuf, expected);
memset(recvbuf, 0, strlen(recvbuf));
int n;
while ((n = recv(sockfd, recvbuf, MAXLEN - 1, 0)) > 0) {
printf("%s",recvbuf);
memset(recvbuf, 0, strlen(recvbuf));
}
close(sockfd);
return 0;
}
我真的不知道为什么出现问题，即使在阅读了RFC 1945和网站的答案之后，我仍然不知道为什么标题不能打印... < / p>
L.E。 ：为什么否定？我问了一个简单的问题，我提供了完整的测试代码+ printscreens。
答案 0 :(得分：4)
这个问题很难理解，因为目前还不清楚到底是什么。只有在查看the previous question时才有意义。
在上一个问题中，OP在命令行上执行了以下操作（实际命令行，而不是HTTP请求）：
GET elf.cs.pub.ro HTTP/1.0
这不是OP所期望的，即向elf.cs.pub.ro发送HTTP / 1.0请求。相反，它使用GET命令（使用LWP perl库执行GET请求）并将第一个参数解释为URL，从而返回http://elf.cs.pub.ro的内容。然后它接受了下一个参数HTTP/1.0，并将其视为另一个URL，即http://HTTP/1.0。特定于用户的环境（或GET命令的细节）HTTP被视为www.http.com，即真实的URL因此是http://www.http.com/1.0。因此，本质上OP执行了两个命令（这里用GET显示，但也可以使用curl或wget或类似命令）：
GET http://elf.cs.pub.ro/
GET http://www.http.com/1.0
在此问题中显示的代码中，OP仅执行第一个请求。要做到第二步，必须为新的目标主机和URL修改程序。