Question

我想创建一个始终打印到屏幕的服务器套接字＆＃34; tick＆＃34; ，如果一个客户端向此服务器发送数据，服务器将打印该数据。我使用非阻塞套接字，但它不起作用，服务器打印到屏幕＆＃34; tick＆＃34;但无法从客户端接收数据。

服务器

int main(int argc, char *argv[]) {
    int server_sockfd, client_sockfd;
    sockaddr_un server_address;
    sockaddr_un client_address;
    int client_len;
    int res;

    /* remove old socket and create unnamed socket */
    unlink("server_socket");
    server_sockfd = socket(AF_UNIX, SOCK_STREAM, 0);

    /* non-blocking socket */
    fcntl(server_sockfd, F_SETFL, O_NONBLOCK);

    /* name the socket */
    server_address.sun_family = AF_UNIX;
    strcpy(server_address.sun_path, "server_socket");
    bind(server_sockfd, (sockaddr*)&server_address, sizeof(server_address));

    /* listen client */
    printf("server_waiting\n");
    listen(server_sockfd, 5);
    client_len = sizeof(client_address);
    client_sockfd = accept(server_sockfd, (sockaddr*)&client_address, (socklen_t*)&client_len);

    while(1) {
        char ch;
        res = recv(client_sockfd, &ch, 1, 0);
        if (res == -1) {
            printf("tick\n");
        }
        else {
            printf("received: %c\n", ch);
        }
    }    
}

客户端

int main(int argc, char *argv[]) {
    int sock_fd;
    struct sockaddr_un address;
    int result;
    char ch = 'A';

    /* create socket for client */
    sock_fd = socket(AF_UNIX, SOCK_STREAM, 0);

    /* name of socket as agreed with server */
    address.sun_family = AF_UNIX;
    strcpy(address.sun_path, "server_socket");

    result = connect(sock_fd, (sockaddr*) &address, sizeof(address));
    if (result == -1) {
            perror("fail\n");
            exit(1);
    }

    /* write via socket */
    send(sock_fd, &ch, 1, 0);
    close(sock_fd);
    exit(0);
}

Answer 1

您正在将列表套接字设置为非阻塞而不是接受的套接字。

遵循您的代码逻辑，您要等待接受呼叫，而不是等待接收呼叫

而不是

/* non-blocking socket */
fcntl(server_sockfd, F_SETFL, O_NONBLOCK);

删除它，然后将fcntl调用添加到您从接受调用中返回的套接字，例如

client_sockfd = accept(....);
int flags = fcntl(client_sockfd, F_GETFL, 0);
fcntl(client_sockfd, F_SETFL, flags | O_NONBLOCK);

accept和fcntl可能会失败，因此您应检查生产代码中的失败。

非阻塞Linux服务器套接字

1 个答案: